Answer:
a.4845ways.
b. 14535ways.
c. 3990ways
d. 1140ways
Step-by-step explanation:
Given data:
No of flavors available to customers = 20.
Solution:
This is permutation and combinations problem,
(a) how many ways can the customers choose 4 different ice creams if they are all of different flavors.
20C4
= n!/(n-k)!)k!
= 20!/(20-4)!)4!
= 20!/(16)!)4!
= 4845ways.
b) are not necessarily of different flavors
Let’s say any two same flavors can be chosen.
20C4 * 3!/2!
= 4845 * 3
= 14535ways.
c) contain only 2 or 3 flavors.
= 20C3 * 3!/2!
= 1140 * 3
= 3420
20C2 * 3
= 190 * 3
= 570.
No of 2 or 3 different flavors
= 3420 + 570
= 3990ways.
d) contain 3 different flavors.
20C3
= n!/(n-k)!)k!
= 20!/(20-3)!)3!
= 1140ways.
Let m and h represent hours Mai spends mowing and hauling, respectively. Then (m+h) will be the number of hours Priya spends babysitting. In order for their earnings to be equal, we must have
7m +14h = 8.40(m+h)
Subtract 7m+8.40h: 5.60h = 1.40m
Divide by 1.40: m = 4h
Then the total number of hours worked by either person is
m + h = (4h) +h = 5h
When only whole numbers of hours are worked, the smallest number of hours that will make earnings equal is 5h, with h=1, or 5 hours. In that time, each will earn 5×$8.40 = $42.
Therefore, each of them must work 5 hours and earn $42 before they go to the movies and Mai will work 4 hours mowing and 1 hour hauling.
Answer:
59.5%
Step-by-step explanation:
22 8 ounce jars out of 37 jars. This is the probability of 22/37. Divide and you get 0.59459, then round.
Answer:
A) 10^23
Step-by-step explanation:
if bases are the same and you're multiplying then:
keep the base and add the exponents
A because if you I want the outcome to be independent then you have to take it out