Question

PLEASE!!!!, can someone help with this Geometry question. I have a quiz.

Answer 1

Step-by-step explanation:

4y-10 and 3x are supplementary angles

so 4y-10+3x=180° (1)

4y-10 and 9x+12 are alternate exterior angles and because we have two parallel lines then these angles are congruent.

so 4y-10=9x+12 (2)

so we have

(1) 4y+3x=180+10

(2) 4y-9x=12+10

(1) 4y=190-3x

we replace this equation to the second equation

190-3x-9x=22

190-22=9x+3x

168=12x

x=168/12

x=14

4y =190-3*(14)=190-42=148

y=148/4=37

3x=3*14=42°

4y-10=4*37-10=148-10=138°

9x+12=9*14+12=126+12=138°