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3 years ago

Which type of data would be best displayed in a histogram

Mathematics

1 answer:

zavuch27 [327]3 years ago

8 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

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Alberto is making a budget. He owes a cell phone bill of $60 per month for 23 more months, plus the fees for any extra usage suc

Elena-2011 [213]

Answer:

Pretty sure it is C

Step-by-step explanation:

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2 years ago

At the beginning of spring, Arianna planted a small sunflower in her backyard. When

zhannawk [14.2K]

Answer:

3 weeks: 21.5 inches

w weeks: 20+0.5w inches

Step-by-step explanation:

Equation: 20+0.5w.

20 was when it was first planted and 0.5 is the amount it grows per week.

6 0

3 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

4 years ago

What is the probability a sample of 90 test takers will provide a sample mean test score within 10 points of the population mean

Elena-2011 [213]

Answer:

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

Step-by-step explanation:

The following information is missing:

The standard deviation of population is 100.

We are given the following information in the question:

Population mean, μ = 502

Standard Deviation, σ = 100

Sample size, n = 90

Standard error =

$\dfrac{\sigma}{\sqrt{n}} = \dfrac{100}{\sqrt{90}} = 10.54$

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(test score within 10 points)

$P(492 \leq x \leq 512) \\\\= P(\displaystyle\frac{492 - 502}{10.54} \leq z \leq \displaystyle\frac{512-502}{10.54}) \\\\= P(-0.9487 \leq z \leq 0.9487)\\= P(z \leq 0.9487) - P(z < -0.9487)\\= 0.829 -0.171 = 0.658 = 65.8\%$

$P(492 \leq x \leq 512) = 65.8\%$

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

7 0

3 years ago

Help me with Thai math it’s worth 22 points PLZZ answer ALL of them

joja [24]

Answer:

supply (B)
A step in process (A)
(b)
(A)

5 0

3 years ago