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kipiarov [429]
3 years ago
15

Write an equation of the line passing through

Mathematics
1 answer:
Korvikt [17]3 years ago
5 0

9514 1404 393

Answer:

  y = 5

Step-by-step explanation:

The given points lie on the horizontal line ...

  y = 5

__

You could write this as 0x+1y=5, but the conventions regarding coefficients of 0 and 1 would have this simplified to y=5.

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Two thirds a number plus 4 is 7
Sergio039 [100]
(2/3)x+4= 7

Subtract 4 from both sides
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3*3/2= 9/2

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Answer:

4Hz

Step-by-step explanation:

Standard form of a sine or cosine function,

y = acos(b(x+c))

where a is the amplitude, b is the value to find the period. and c is the phase shift.

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From the equation given in the question,

y = 3cos(8\pi \: t +  \frac{\pi}{2} ) \\ y = 3cos(8\pi(t +  \frac{1}{16} )) \:  \: (factorising \: 8\pi \: out)

We can see:

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4 0
2 years ago
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PLEASE HELP ASAP!!!!
Setler [38]

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.

To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.

Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.

Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.

Therefore:

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 8}  \\ f(4) = 3 \end{cases}}

The nth root of a can contain negative number only if n is an odd number.

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 2 \times -  2 \times   - 2}  \\ f(4) = 3 \end{cases}} \\  \large{  \begin{cases} f( - 8 ) =  - 2\\ f(4) = 3 \end{cases}}

Answer

  • f(-8) = -2
  • f(4) = 3
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