a given sample of a gas has a volume of 3.0 L at a pressure of 4.0 atm. If the temperature remains constant and the pressure is
changed to 6.0 atm, what is the new volume?
1 answer:
Answer:-
2.0 L
Explanation:-
Initial Volume = V 1 = 3.0 L
Initial Pressure P 1 = 4.0 atm
New pressure P 2 = 6.0 atm
Using boyle's law
P1 V1 = P2 V2
New Volume V2 = P1 V1 / P2
= 4.0 atm x 3.0 L / 6.0 atm
= 2 .0 L
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