Explanation:
substance Q could be <em><u>oxygen (O2)</u></em>
substance R could be <em><u>carbon</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>o</u></em><em><u>x</u></em><em><u>i</u></em><em><u>d</u></em><em><u>e</u></em><em><u> </u></em><em><u>(</u></em><em><u>C</u></em><em><u>O</u></em><em><u>2</u></em><em><u>)</u></em>
<em><u>A molecule </u></em><em><u>can </u></em><em><u>possess polar bonds and still be nonpolar.</u></em>
I hope this helped. Have a nice day, make sure to take care of yourself. You're loved <3
Entropy change is defined only along the path of an internally reversible process path.
<h3><u>What is Entropy Change </u>?</h3>
- Entropy is a measure of a thermodynamic system's overall level of disorder or non-uniformity. The thermal energy that a system was unable to use to perform work is known as entropy.
- Entropy Change is a phenomena that measures how disorder or randomness have changed inside a thermodynamic system.
- It has to do with how heat or enthalpy is converted during work. More unpredictability in a thermodynamic system indicates high entropy.
- Entropy is a state function, hence it is independent of the direction that the thermodynamic process takes.
- The rearranging of atoms and molecules from their initial state causes the change in entropy.
- This may result in a decrease or rise in the system's disorder or unpredictability, which will, in turn, result in a corresponding drop or increase in entropy.
To view more questions about entropy change, refer to:
brainly.com/question/4526346
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Answer:
400 mL
Explanation:
Given data:
Mass of barium = 2.17 g
Pressure = 748 mmHg (748/760 = 0.98 atm)
Temperature = 21 °C ( 273+ 21 = 294k)
Milliliters of H₂ evolved = ?
Solution:
chemical equation:
Ba + 2H₂O → Ba(OH)₂ + H₂
Number of moles of barium:
Number of moles = mass/ molar mass
Number of moles = 2.17 g / 137.327 g/mol
Number of moles = 0.016 mol
Now we will compare the moles of barium with H₂.
Ba : H₂
1 : 1
0.016 : 0.016
Milliliters of H₂:
PV = nRT
V = nRT/P
V = 0.016 mol × 0.0821 atm. mol⁻¹.k⁻¹.L×294 k/0.98 atm
V = 0.39 atm. L/0.98 atm
V = 0.4 L
L to mL
0.4 × 1000 = 400 mL
