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sveticcg [70]
3 years ago
6

20 POINTS!!

Chemistry
1 answer:
Andrews [41]3 years ago
3 0

Answer:

B. Interferon

Explanation:

interferon targets any lingering melanoma cells and prevents them from spreading and growing.

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Given the balanced equation representing a reaction: HCl + H₂O → H₃O⁺ + Cl⁻ The water molecule acts as a base because it
Wittaler [7]

Answer:

accepts an H⁺

Explanation:

The following balanced ionic equation is given in this question;

HCl + H₂O → H₃O⁺ + Cl⁻

According to Brønsted–Lowry acid–base theory, a base is any substance that can accept hydrogen ions or protons (H+). Using this definition for the above equation, water (H2O) accepts a proton or H+ that was donated by HCl to form H30+ (hydronium ion), hence, water is acting as a BASE in this reaction because it accepts an H+.

5 0
3 years ago
Look at the reaction below. Which substance is the base in the reaction? 2H2O (l) H2SO4 (aq) CaSO4 (aq) Ca(OH)2 (aq)
dsp73

Ca(OH)2 (aq) because of elements oxygen and hydrogen

Ca(OH)2(aq)+H2SO4(aq)—→ CaSO4(s)+ 2H2O(l)

6 0
3 years ago
A food substance kept at 0°C becomes rotten (as determined by a good quantitative test) in 8.3 days. The same food rots in 10.6
ZanzabumX [31]

Answer:

1.   67.2 kJ/mol

Explanation:

Using the derived expression from Arrhenius Equation

In \ (\frac{k_2}{k_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})

Given that:

time t_1 = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time t_2 = 10.6 hours

Temperature T_1 = 0° C = (0+273 )K = 273 K

Temperature T_2 = 30° C = (30+ 273) = 303 K

Rate = 8.314 J / mol

Since (\frac{k_2}{k_1}=\frac{t_2}{t_1})

Then we can rewrite the above expression as:

In \ (\frac{t_2}{t_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})

In \ (\frac{199.2}{10.6}) = \frac{E_a}{8.314}(\frac{303-273}{273*303})

2.934 = \frac{E_a}{8.314}(\frac{30}{82719})

2.934 = \frac{30E_a}{687725.766}

30E_a = 2.934 *687725.766

E_a = \frac{2.934 *687725.766}{30}

E_a =67255.58 \ J/mol

E_a =67.2 \ kJ/mol

7 0
3 years ago
Avoiding an accident when driving can depend on reaction time. That time, measured in seconds from the moment the driver see dan
crimeas [40]

Answer:

The answer is below

Explanation:

A normal model is represented as (μ, σ). Therefore for (1.5, 0.18), the mean (μ) = 1.5 and the standard deviation (σ) = 0.18

The z score shows by how many standard deviations the raw score is above or below the mean. It is given as:

z=\frac{x-\mu}{\sigma}

a) For x < 1.35 s

z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.35-1.5}{0.18}=-0.83

From the normal distribution table, the percent of drivers have a reaction time less than 1.35 seconds = P(x < 1.35) = P(z < -0.83) = 0.2033 = 20.33%

b) For x > 1.9 s

z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.9-1.5}{0.18}=2.22

From the normal distribution table, the percent of drivers have a reaction time greater than 1.9 seconds = P(x > 1.9) = P(z > 2.22) = 1 - P(z<2.22) = 1 - 0.9868 = 0.0132 = 1.32%

c) For x = 1.45

z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.45-1.5}{0.18}=-0.28

For x = 1.75

z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.75-1.5}{0.18}=1.39

From the normal distribution table, P(1.45 < x < 1.75) = P(-0.28 < z < 1.39) = P(z < 1.39) - P(z< - 0.28) = 0.9177 - 0.3897 = 0.528 = 52.8%

d) A percentage of 10% corresponds to a z score of -1.28

z=\frac{x-\mu}{\sigma}\\\\-1.28=\frac{x-1.5}{0.18}\\\\x-1.5=-0.2034\\\\x=1.27

e) P(z < z1) - P(z< -z1) = 60%

P(z < z1) - P(z< -z1) = 0.6

P(z < -z1) = 1 - P(z < z1)

P(z<z1) - (1 - P(z < z1)) = 0.6

2P(z<z1) - 1= 0.6

2P(z<z1) = 1.6

P(z<z1) = 0.8

From the z table, z1 = 0.85

0.85=\frac{x-1.5}{0.18}and-0.85=\frac{x -1.5}{0.18}  \\\\x=1.65 \ and\ x=1.35

The reaction time between 1.35 and 1.65 seconds

8 0
3 years ago
10g of helium (MM=4.0g/mol) occupies a volume of 73L at a temperature of 233k. calculate the pressure of this gas
Levart [38]
PV = nRT   (where P = pressure; V = volume; n = number of moles; R = gas constant; T = Temperature)
Moles of He = mass of He ÷ molar mass of He                    =  10 g ÷ 4 g/mol                    =  2.5 mol

Now, based on the formula above     P = (nRT) ÷ V
    P = (2.5 mol × (0.082 L · atm/mol · K) × 233 K) ÷  73 L        ≈  0.65 atm
8 0
3 years ago
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