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Deffense [45]
3 years ago
11

I WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
barxatty [35]3 years ago
3 0

Answer:

The answer is the middle one. The one starting with 27...

Step-by-step explanation:

Hope this helps!

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If you could provide a picture of the graph that would be very helpful
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To convert 0.7 hours into minutes, which ratio could you multiply by? Remember that 1 hour = 60 minutes.
ira [324]
0.7hr(60min/hr)=42 min

The ration you multiplied by was 60min/hr, to cancel out the hr unit label...
3 0
3 years ago
I NEED HELP!!! PLEASE HELP!!! FIRST TO ANSWER GETS 50 POINTS AND BRAINLIEST ANSWER!!! HEEELLPPPP!!!! Find the distance between p
daser333 [38]

Answer:

8.6 to the nearest tenth.

Step-by-step explanation:

Using the distance formula d =  √ [(y2 - y1)^2 + (x2 - x1)^2] where (x1, y1) and (x2, y2) are the two endpoints.

= √ (4 - -3)^2 + (-3-2)^2

= √(49 + 25)

= 8.60

6 0
3 years ago
A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
professor190 [17]

Answer:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

n=15 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =16 represent the sample variance

\sigma^2_0 =25 represent the value that we want to  verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And replacing we got:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0
3 years ago
Help me answer this please!!!
emmasim [6.3K]

Answer:

ok

Step-by-step explanation:

ok

8 0
3 years ago
Read 2 more answers
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