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Setler [38]
3 years ago
13

Solve 6x + 5 = 3x + 14 It needs to be written in a step by step way of how to do it xx

Mathematics
2 answers:
OlgaM077 [116]3 years ago
7 0
You must solve for x in order to balance the equations.

x= 3

6(3)+5=3(3)+14

18+5= 9+14, which is 23=23

x equals 3 and both equations equal to 23.

Please vote my answer brainliest! Thanks.
Lemur [1.5K]3 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

6x + 5 = 3x + 14

6x - 3x = 14 - 5

3x = 9

x = 9/3

x = 3

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PLEASE HELP!!!if the unit rate for the line B is 7meters/seconds , which if the following is not a possible value for the unit r
Cerrena [4.2K]

Answer:

The answer is "A", 6.3 meters/second because it is lower than 7 when it is supposed to be higher.

I hope this helped and please mark me as brainliest!

4 0
2 years ago
A skydiver jumps from an airplane at an altitude of 2,500 ft. He falls under the force of gravity until he opens his parachute a
Leviafan [203]
I think the answer is 2.5
7 0
3 years ago
Does 26/3 equal 182/21
Tatiana [17]

Answer:

Yes!

Step-by-step explanation:

26/3 is a seventh of 182/21

Divide 182 and 21 both by 7, and you get 26/3. So, yes, it is equivalent.

8 0
3 years ago
What is the amplitude of the cosine function corresponding to the secant function graphed below ? a. -2 b. -1 c. 2 d. 3
Bas_tet [7]

Answer:

2

Step-by-step explanation:

From the graph, we obtain the trigonometric function as:

y=2 \sec x+1

The corresponding cosine function have equation.

y=2\cos x+ 1

This function is of the form: y=a\cos bx+c

where |a| is the amplitude.

Therefore the amplitude is |2|=2

The third choice is correct

7 0
4 years ago
fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many
storchak [24]

Answer:

Both fireworks  will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

Speed of Firework B=240 ft/s

Time before which fire work b is launched =0.25s

To Find:

How many seconds after firework b launches will both fireworks explode=?

Solution:

Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

Firework A= 330(t)

Firework B=240(t)+240(0.25)

Since we need to know the same time after which they explode, we can equate both the equations

330(t) = 240(t)+240(0.25)

300(t)= 240(t)+60

300(t)-240(t)= 60

60(t)=60

t=\frac{60}{60}

t=1

7 0
3 years ago
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