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2 years ago

Calculate the size of angle V on the square named FTLP. 18 cm F T c 6 P

Mathematics

1 answer:

Greeley [361]2 years ago

4 0

Given :

A square of side 18 cm.

To Find :

Angle V on the square.

Solution :

This problem can be done easily without using pen and paper but we need to know the property of diagonal of square given below :

The diagonals of the square bisect each other at 90°.

This will hold true for any right angle triangle.

Therefore, the angle V on the square is 90°.

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Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation

Black_prince [1.1K]

<u>Define x:</u>

Let the first number be x.

1st number = x
2nd number = x + 1
3rd number = x + 2

<u>Construct equation:</u>
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)

Answer: 3x + 3 = 4(x + 1)

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3 years ago

What is the greatest common factor of 40 and 36

Kazeer [188]

Nobody goes around with lists of greatest common factors in their head.
When we need to know one, we grab the nearest pencil and work it out.

The factors of 40 are 1, 2, 4, 5, 8, 10, 20, and 40 .

The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36 .

The common factors of 35 and 40 are 1, 2, and 4 .

The biggest one is 4 .

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3 years ago

Read 2 more answers

IN THE FIGURE 5.24 TO THE RIGHT ABCD IS A RHOMBUS.SHOW THAT AC IS THE BISECTOR OF <BAD.

Inessa05 [86]

In any rhombus, the four sides are the same length.

Because of this, we know that

AD = AB
CD = BC

Furthermore, AC = AC due to the reflective property

Those three facts then allow us to prove triangle ACD is congruent to triangle ACB through the SSS congruence property. Then from CPCTC, we then know that angle DAC = angle BAC, which is enough to show that AC bisects the angle shown. The term "bisect" means "cut in half".

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2 years ago

The angle between 2 curves at a point of intersection is the angle between their tangent lines.Find acute between y=x^2 and y=x^

Vikentia [17]

I uploaded the answer to $^{}$ a file hosting. Here's link:

bit. $^{}$ ly/3gVQKw3

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3 years ago

When A’B’C’ is reflected across the line x= -2 to from A”B”C”, vertex ___ of A”B”C” will have the same coordinates as B’

Lesechka [4]

Answer: B''

This is because point B' has x coordinate x = -2. This point is directly on the mirroring line, so it doesn't move when the reflection is applied.

We can write B' = B''

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3 years ago