Answer:
see below
Step-by-step explanation: 5 27 7 16
area = 1/2 bh
height of a triangle is 7 ft more than its base
base = b
height = b + 7
area = 30
area = 1/2 b(h)
30 = 1/2 b(b + 7)
30 = 0.5(b²+ 7b)
30 = 1/2 b²+ 3.5b solve for b
1/2 b²+ 3.5b = 30
1/2 b²+ 3.5b - 30 = 0
b²+ 7b - 60 = 0 factor
(b +12)(b - 5) = 0 when b = -12 or 5 base length can't be negative
b = base = 5
area = 1/2 bh 1/2×2(9) = 9
area = 1/2 bh 1/2×5(12) = 60
area = 1/2 bh 1/2×9(16) = 56
area = 1/2 bh 1/2×12(19) = 114
CHECK THE ATTACHED FIQURE FOR THE BRIDGE
Answer:
60 ft
Step-by-step explanation:
From the question we know that triangles ABC and EDC are in a 1:1 with this given ratio it implies that
triangles ABC and EDC are congruent then we can say
side EC = side AC
3x + 9 = 5x - 5
Then we can simplify to know value of x
3x + 14= 5x
2x = 14
x = 7
But we know that AC= 5x - 5 , then substitute value of x into it
AC = 5x + 5 = 5(7) - 5
= 35 - 5
AC= 30 ft
Also EC= 3x + 9 then substitute value of x into it
EC = 3x + 9 = 3(7) + 9
= 21 + 9
EC= 30 ft
Then the the distance between the top and bottom of the bridge, in feet, = EC+AC
= 30 + 30 = 60 ft
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Answer:
Radius length: √5
Standard Form (Equation): (x + 4)^2 + y^2 = 5
Step-by-step explanation:
First we will determine the radius;
Center: (-4, 0)
Point on Circumference: (-2, 1)
d = √(-2 - (-4))^2 + (1 - 0)^2 = √(2)^2 + (1)^2
= √4 + 1 = √5
Therefore the radius is of length √5
Now the equation of a circle is in the form ((x - h)^2 + (y - k)^2) = r^2. The center is in the form (h,k) and r is the radius. Given this our equation would be (x - (-4))^2 + (y - 0)^2 = (√5)^2, or [simplified] (x + 4)^2 + y^2 = 5.
Answer:
bbb
A
c
d
Step-by-step explanation:
