Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
B. subtract the frequency of the recessive allele from 1.
D) take in nutrients because endocytosis is the process when a cell takes in food
Answer:
Y- x+ Y-
Explanation:
when an atom loses electrons the atom the result is a positive ion. when an atom gains an electron, the result is a negative ion
