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3 years ago

A student determines that a 1.5 g mixture of CaCO3(s) and

Chemistry

1 answer:

zysi [14]3 years ago

7 0

We are given:

Mass of the mixture = 1.5 grams

Number of Moles of NaHCO₃ = 0.01 mole

Mass of 0.01 moles of NaHCO₃:

Mass = number of moles * Molar mass

Mass = 0.01 * 84

Mass = 0.84 grams

Mass% of Na in NaHCO₃:

Molar mass of NaHCO₃ = 84 grams/mol

Molar mass of Na = 23 grams / mol

Mass% = (Molar mass of Na / Molar mass of NaHCO₃) * 100

Mass% = (23/84) * 100

Mass% = 27%

Mass of Na in 0.01 moles:

Since the Mass% of Na is 27% and the total mass is 0.84 grams

So, we can say that 27% of 0.84 is the mass of Na

Mass of Na = 0.84 * 0.27

Mass of Na = 0.23 grams

Mass% of Na in the mixture:

Total mass of the mixture = 1.5 grams

Mass of Na in the mixture = 0.23 grams

Mass% of of Na in the Mixture = (Mass of Na / Mass of Mixture) * 100

Mass% of Na = (0.23 / 1.5) * 100

Mass% of Na = 15.3%

Therefore, we have 15.3% Na in the given mixture by mass

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What is the difference between an atom and ion. What makes an ion an ion?

tresset_1 [31]

Answer:

atoms are neutral or they have equal number of proton and electron but ions can be cation(positively charged) or anion(negatively charged) based on the number of electron the atm lose and gain respectively

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4 years ago

Determine the mass of each of t he following:

EastWind [94]

Explanation:

Mass of compounds = Moles of compound × Molecular mass of compound

a) Moles of LiCl = 2.345 mol

Molecular mass of LiCl = 42.5 g/mol

Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g

b) Moles of acetylene = 0.0872 mol

Molecular mass of acetylene= 26 g/mol

Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g

c) Moles of sodium carbonate= $3.3\times 10^{-2}mol$

Molecular mass of sodium carbonate= 106 g/mol

Mass of $3.3\times 10^{-2}mol$ sodium carbonate

= $3.3\times 10^{-2}mol\times 106 g/mol$ = 3.498 g

d) Moles of fructose = $1.23\times 10^3 mol$

Molecular mass fructose= 180 g/mol

Mass of $1.23\times 10^3 mol$ fructose

= $1.23\times 10^3mol\times 180 g/mol = 221,400 g$

e) Moles of $FeSO_4(H_2O)_7=0.5758 mol$

Molecular mass of $FeSO_4(H_2O)_7 =278 g/mol$

Mass of $1.23\times 10^3 mol$ fructose

= $0.5758 mol\times 278 g/mol= 160.0724 g$

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3 years ago

Jill then wrote the formulas for all the possible compounds that sodium can form with the other ions. What formulas did she writ

sp2606 [1]

Explanation:

Sodium has atomic number of 11 and its electronic configuration is given by:

$[Na]=1s^22s^22p^63s^1$

The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.

$Na\rightarrow Na^++1e^-$

$[Na^+]=1s^22s^22p^63s^0$

Sodium has single valency that is 1.

Let nbe the valency of the ion 'X'

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

$Na_nX_1$