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navik [9.2K]
3 years ago
5

What is a pure substance - bread, salt, seawater, or soil?

Chemistry
2 answers:
Kisachek [45]3 years ago
7 0

Answer: Salt is a pure substance. Pure substances are composed of one type of molecule. All of the substances listed are composed of two or more types of molecules, except for salt. Therefore, salt would be your answer.

Hope this helps.

miv72 [106K]3 years ago
5 0

Answer:

Salt is the pure substance out of them all.

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How many forces act on each person? When they put there hands together or High five
EastWind [94]

Answer:

Left and right: two forces

Total: four forces

Explanation:

If it's just the forces that they are using it would be two the force of each person's hand on the other. However there is also gravity pulling down on their hand but they use another force to pull it up which you can call the normal force.

if this helped please hit the thanks button <3

6 0
3 years ago
Read 2 more answers
HELP PLEASEEEEE KAJAMAAKAOAAJAKAKJSMALASJSSJKSSKSJSMKSLWWMSMSKLSSLSKSMMSMSKSKSOSKSSMMSMSKSKSSKMSMSMSMSKSMMSNSSMMSMSMSMSMSKSKSLSL
wariber [46]

Answer:

the cirle of life

Explanation:

i am smart

8 0
2 years ago
Involves two atoms sharing 4 electrons
babymother [125]
Covalent bond should be right
4 0
3 years ago
........URGENT PLEASE HELP............
Yuri [45]

Answer:

12.0778

Explanation:

6 0
2 years ago
Does anybody know how to do q4. Please show working out thanks.
insens350 [35]

Answer:

% purity of limestone = 96.53%

Explanation:

Question (4).

Weight of impure CaCO₃ = 25.9 g

Molecular weight of CaCO₃ = 40 + 12 + 3(16)

                                              = 100 g per mole

We know at S.T.P. number of moles of CO₂ = 1 and volume = 22.4 liters

From the given reaction, 1 mole of CaCO₃ reacts with 1 mole or 22.4 liters of

CO₂.

∵ 22.4 liters of CO₂ was produced from CaCO3 = 100 g

∴ 1 liter of CO₂ will be produced by CaCO₃ = \frac{100}{22.4}

∴ 5.6 liters of CO₂ will be produced by CaCO₃ = \frac{100\times 5.6}{22.4}

                                                                              = 25 g

Therefore, % purity of CaCO₃ = \frac{\text{Weight calculated}}{{\text{Weight given}}}\times 100

                                                 = \frac{25}{25.9}\times 100

                                                 = 96.53 %

7 0
3 years ago
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