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3 years ago

Plssssss help me!!!

Mathematics

1 answer:

Fofino [41]3 years ago

3 0

Answer:

2h + 10

Step-by-step explanation:

The question gives one the height of Tree A (8h - 1) and the height of Tree B (6h - 11). The problem asks one to find how much taller Tree A is than Tree B. This problem can be modeled using a simple subtraction problem, the height of Tree A, minus the height of Tree B. Remember to distribute the subtraction sign outside of the parenthesis, and only combine like terms;

(Tree A) - (Tree B)

= (8h - 1) - (6h - 11)

= 8h - 1 - 6h + 11

= 2h + 10

Since there was no numerical value given for the variable (h), nor any value which this expression is equal, the final answer is (2h + 10).

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Alenkasestr [34]

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3 years ago

Two cars are driving towards an intersection from perpendicular directions.

FrozenT [24]

For a better understanding of the solution provided here please find the diagram in the attached file.

In the diagram, A is the intersection. B is the position of the first car and C is the position of the second car. As can be clearly seen, as per the directions given in the question, the cars and the intersection make a right triangle.

The distance between the first car and the intersection is $x$ and the distance between the second car and the intersection is $y$ . The distance between the two cars is depicted by $s$ . As we can see, $s$ is the hypotenuse of the right triangle. At the given instance the distances are 8 meters and 6 meters respectively. Thus, by the Pythagorean Theorem the hypotenuse will be:

$s=\sqrt{8^2+6^2}= \sqrt{100}=10$ ...............(Equation 1)

Now, we know that at any instant the Pythagorean Theorem holds and so we will have, in general:

$s^2=x^2+y^2$

Now, implicitly differentiating the above formula with respect to time, we get:

$2s\frac{ds}{dt}=2x \frac{dx}{dt}+2y \frac{dy}{dt}$

This can be further simplified by dividing both the sides by the common factor 2 as:

$s\frac{ds}{st}=x \frac{dx}{dy}+y\frac{dy}{dt}$ .................(Equation 2)

As we can see from the questions and the diagram, $\frac{dx}{dt}=-2 m/s$ and $\frac{dy}{dt}=-9 m/s$ . The negative sign is there because the distances y and x are reducing as the cars approach the intersection.

Applying this knowledge to (Equation 2) along with the fact that as per (Equation 1), $s=10$ , we get (Equation 2) to become:

$10\times \frac{ds}{dt}=8\times -2+6\times -9=-70$

Therefore, $\frac{ds}{dt}= \frac{-70}{10}=-7 m/s$

Thus, the rate of change of the distance between the cars at the given instant (in meters per second) is $-7$ .

Therefore, out of the given options, option D is the correct one.

4 0

3 years ago

28 members and 50% decrease

stellarik [79]

50% is half, and half of 28 is 14.

So your answer is 14 members.

Hope this helped! (:

6 0

4 years ago

Read 2 more answers

A baker is calculating the charge for two types of cookies.

eimsori [14]

Answer:

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5 0

3 years ago

Which has the same value as 1 hundred 7 tens 70 tens 17 tens 10 tens 7 tens

N76 [4]

When they say tens you're basically adding a zero at the end of the number. So 1 hundred 7 tens would be 170, 70 tens would be 700, 17 tens would be 170, 10 tens would be 100, and 7 tens is 70.

5 0

4 years ago