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spayn [35]
3 years ago
8

Which statement is true about the circumference of a circle?

Mathematics
2 answers:
Gemiola [76]3 years ago
6 0
The answer should be d because the circumference is 2 time pie r squared
notsponge [240]3 years ago
6 0
I believe it is C circumference is 2piR
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The total amount of money earned by all three plumbers on Monday was $1,400. On Tuesday they earned a total of $1,660, and on We
Alekssandra [29.7K]
Set of equations that can be used to calculate rate for each plumber:
2A+8B+8C = 1,400 --- (1)
4A+7B+10C = 1,660 --- (2)
3A+9B+9C = 1,660 --- (3)
------------------------------------
2*(1) - (2)
------------------------------------
4A+16B+16C = 2,800
4A+7B+10C = 1,660 -
------------------------------------
       9B+6C = 1,140 --- (4)
------------------------------------
3(2) -4(3)
-----------------------------------
12A+21B+30C = 4,980
12A+36B+36C = 6,600 -
-----------------------------------
         -15B-6C = -1,620 --- (5)
------------------------------------
(4) + (5)
------------------------------------
9B+6C = 1140
-15B-6C = -1620 +
-------------------------------------
-6B = -480 => 6B = 480 => B = 480/6 = 80
-------------------------------------------------------
Using (4), 9(80)+6C = 1140
720+6C = 1140 => 6C = 1140-720 = 420 => C = 420/6 = 70
------------------------------------------------------------------------------
Using (1), 2A+8(80)+8(70) = 1400
2A+640+560 =1400 => 2A = 1400-640-560 = 200 => A = 200/2 = 100
----------------------------------------------------------------------------------------------
The rates are:
A = $100
B = $80
C = $70
--------------------------------
On Thursday, number of calls: A = 4 hrs, B = 6 hrs, C = 3 hrs
Money earned = 4*100+6*80+3*70 = $1,090
6 0
4 years ago
Read 2 more answers
How does the setting of a story influence a characters feelings and actions?
Ratling [72]

Answer + Step-by-step explanation:

Settings can affect the character in a number of ways.

For example, it can cause conflict and influence the character's

actions. In the setting of a war, it will obviously cause conflict

for a character or change the character's attitude towards another

character whom they probably knew well. The setting can affect the mood

and tone of the scene, resulting in many actions the reader did not think was

going to happen before.

<u><em>Hope this helps, feel free to message me in the comments</em></u>

<u><em>if my answer is wrong ;)</em></u>

<u><em></em></u>

- genius423

6 0
3 years ago
Problem 7.43 A chemical plant superintendent orders a process readjustment (namely shutdown and setting change) whenever the pH
vaieri [72.5K]

Complete Question

Problem 7.43

   A chemical plant superintendent orders a process readjustment (namely shutdown and setting change) whenever the pH of the final product falls below 6.92 or above 7.08. The sample pH is normally distributed with unknown mu and standard deviation 0.08. Determine the probability:

(a)

of readjusting (that is, the probability that the measurement is not in the acceptable region) when the process is operating as intended and \mu = 7.0 probability

(b)

of readjusting (that is, the probability that the measurement is not in the acceptable region) when the process is slightly off target, namely the mean pH is \mu = 7.02

Answer:

a

The value is  P(X < 6.92 or X > 7.08 ) =  0.26431  

b

The value  is P(X < 6.92 or X > 7.08 ) =  0.29344  

Step-by-step explanation:

From the question we are told that

  The mean is  \mu =  7.0

  The standard deviation is  \sigma  =  0.08

Considering question a

Generally the probability of readjusting when the process is operating as intended and mu  7.0 is mathematically represented as

       P(X < 6.92 or X > 7.08 ) =  P(X <  6.92  ) + P(X > 7.08)

=>    P(X < 6.92 or X > 7.08 ) =  P(\frac{X - \mu }{\sigma} < \frac{6.9 - 7}{0.08}  ) + P(\frac{X - \mu}{\sigma} >  \frac{7.08 - 7}{0.08} )

Generally

 \frac{X - \mu }{\sigma} = Z(The \  standardized \  value \ of \  X)

So

=> P(X < 6.92 or X > 7.08 ) =  P(Z < \frac{6.9 - 7}{0.08}  ) + P(Z >  \frac{7.08 - 7}{0.08} )    

=> P(X < 6.92 or X > 7.08 ) =  P(Z < -1.25) + P(Z >  1 )  

From the z table the probability of  (Z < -1.25) and  (Z >  1 ) is  

       P(Z < -1.25) =  0.10565

and

      P(Z >  1 ) = 0.15866

So

=> P(X < 6.92 or X > 7.08 ) =  0.10565 + 0.15866      

=> P(X < 6.92 or X > 7.08 ) =  0.26431      

Considering question b

Generally the probability of readjusting when the process is operating as intended and mu  7.02 is mathematically represented as

       P(X < 6.92 or X > 7.08 ) =  P(X <  6.92  ) + P(X > 7.08)

=>    P(X < 6.92 or X > 7.08 ) =  P(\frac{X - \mu }{\sigma} < \frac{6.9 - 7.02}{0.08}  ) + P(\frac{X - \mu}{\sigma} >  \frac{7.08 - 7.02}{0.08} )

Generally

 \frac{X - \mu }{\sigma} = Z(The \  standardized \  value \ of \  X)

So

=> P(X < 6.92 or X > 7.08 ) =  P(Z < \frac{6.9 - 7.02}{0.08}  ) + P(Z >  \frac{7.08 - 7.02}{0.08} )    

=> P(X < 6.92 or X > 7.08 ) =  P(Z < -1.5) + P(Z >  0.75 )  

From the z table the probability of  (Z < -1.5) and  (Z >  0.75 ) is  

       P(Z < -1.5) = 0.066807

and

      P(Z >  0.75 ) = 0.22663

So

=> P(X < 6.92 or X > 7.08 ) = 0.066807 + 0.22663      

=> P(X < 6.92 or X > 7.08 ) =  0.29344      

6 0
3 years ago
Please and thank you so much!
Amiraneli [1.4K]

Answer:

sorry i don't know the answer

Step-by-step explanation:

3 0
3 years ago
What are the answers?
madam [21]
Positive numbers is the last one
7 0
3 years ago
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