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ch4aika [34]
3 years ago
14

20 POINTS I need your help

Mathematics
2 answers:
alexira [117]3 years ago
7 0

Step-by-step explanation:

{( \frac{ {5}^{7} \times  {( - 3)}^{4}  }{ {5}^{6} } )}^{2}  =  {( ({5}^{7 - 6} ) \times  {( - 3)}^{4} )}^{2}  \\  =  {5}^{2}  \times  {( - 3)}^{4 \times 2}  =  {5}^{2}  \times  {( - 3)}^{8}

25 * 6561= 164,025

disa [49]3 years ago
6 0
The answer to your question is 405
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Answer:

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3 years ago
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
Read 2 more answers
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3 years ago
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4. Simplify the expression. (6 points)
Lunna [17]

<span>4. Simplify the expression.
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</span><span>5. Find all solutions in the interval [0, 2π). (6 points)
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3 0
3 years ago
Read 2 more answers
This figure consists of a rectangle and semicircle.
noname [10]

Answer:

Step-by-step explanation:

A = LW + ½πr²  

A = 15(12) + ½(3.14)(12²/4)

A = 180 + 56.52

A = 236.52 m²

3 0
2 years ago
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