It should be negative one (-1)
$10.29 (14.7)(.3)= 4.41. 14.7-4.41
Answer:
It is 24^21 without hesitation
One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
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Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
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