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3 years ago

How many ways can an employer send 3 employees to a job fair if she has 11 employees?

Mathematics

1 answer:

eimsori [14]3 years ago

6 0

She can send 3 employees to a job fair with 11 employees 165 different ways.

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Given the side lengths below, which would not create a right triangle? A. 5, 12, 13 B. 8, 15, 17 C. 6, 8, 10 D. 5, 10, 15

storchak [24]

Answer:

the answer is D. 5, 10, 15

4 0

3 years ago

Nine out of ten students prefer math class over lunch. How many students do not prefer math if 200 students were asked?

fredd [130]

So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.

3 0

3 years ago

The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.

12345 [234]

<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

$34 = 2(L + 6.5)$

Thus the equation is found

<em><u>Solve for "L"</u></em>

$L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5$

Thus length of rectangle is 10.5 units

6 0

3 years ago

PLEASE HURRY UP I WILL MARK YOU BRAINLYESTWith the passing of the 13th, 14th, and 15th Amendments to the U.S.Constitution, discr

andrey2020 [161]

Answer:

as that guy who commented said, its civil war amendments

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please answer me question 3 solving part

Illusion [34]

Answer:

1. D

2. B

3. A

Step-by-step explanation:

Question 1:

The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.

Question 2:

Given that <KLM = x°

<KML = 50°

<JKL = (2x - 15)°

According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.

2x - 15 = x + 50

Solve for x

2x - x = 15 + 50

x = 65

Therefore, <KLM = 65°

QUESTION 3:

<JKL = 2x - 15

Plug in the value of x

<JKL = 2(65) - 15

= 130 - 15

<JKL = 115°

7 0

3 years ago