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Elden [556K]
3 years ago
8

Consider the sequence: 11, 21, 31, …, … , … What is the nth term of this sequence ?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0
I would say that the "n"th term of the sequence is 41, as the pattern increases by 10 every term.
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Two trains left the station traveling in opposite directions. The distance Train A traveled is modeled by the function d(t)=81t
stira [4]

Answer:

Option A -  The distance Train A traveled in 1 h is equal to the distance Train B traveled in 1 h.

Step-by-step explanation:

Given : The distance Train A traveled is modeled by the function d(t)=81t

where d represents distance in miles and t represents time in hours.

To find : How does the distance Train A traveled in 1 hour compare to the distance Train B traveled in 1 hour?

Solution :

Distance traveled by Train A in 1 hour is

d(t)=81t

d(t)=81(1)=81

Distance traveled by Train B in 1 hour is

d(t)=81t

d(t)=81(1)=81

or for B, we have 324 miles in 4 hours. If that is at a constant speed, it travels 324/4 = 81 miles in one hour

Therefore, The distance Train A traveled in 1 h is equal to the distance Train B traveled in 1 h.

Hence, Option A is correct.


8 0
2 years ago
How much interest will be earned on a $6,000 investment at 2.25% for 5 years. Round to the
Monica [59]

Final amount = 6675, interest earned will be 675

3 0
3 years ago
2% of 250 this is worth probaly eleven points plz help me find the percent of the quantity ​
lapo4ka [179]

Answer:

= 5

Step-by-step explanation:

(2/100) × (250/1)

multiply the numerators

500/100

5/1

= 5

7 0
3 years ago
What is the factored form of x^3-1
polet [3.4K]

Answer:

the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

Step-by-step explanation:

We need to find factors of x^3 -1

x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\

So, the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

7 0
3 years ago
wallpaper is sold in rolls that are 2 feet wide what is the minimum length you would need to purchase to cover the wall and 60 f
vredina [299]

Answer:

<h3>28feet</h3>

Step-by-step explanation:

Let the wallpaper be a rectangle

Area of a rectangle = Length * Width

A = LW

Perimeter P = 2L+2W

If the wallpaper is sold in rolls that are 2 feet wide, then the width is 2 feet, to get the length, substitute W = 2 and P = 60 into the formula for calculating the perimeter of a rectangle.

60 = 2L + 2(2)

60 = 2L + 4

2L = 60-4

2L = 56

L = 56/2

L = 28

<em>The minimum length that will be purchased to cover the wall is 28 feet</em>

5 0
3 years ago
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