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avanturin [10]
3 years ago
5

Please Help!!!!!!!!!!!!

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

7

Step-by-step explanation:

since 6-2=4 i assume that it's the same for 9 which equals 7

this may or may not be wrong

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The factored form is 25y^2 + 8 if the 2 was supposed to be an exponent.
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I dont know who is up but if you are open a another tab on your laptop and look up loser .com
Volgvan

Answer:

I did and I must say I don't know what I was expecting but he deserved it.

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What is the volume of the cone with radius 3 ft and height 5 ft? Express the answer in terms of π.
I am Lyosha [343]

Answer:

V = 15 pi ft^3

Step-by-step explanation:

The volume of a cone is given by the formula

V=1/3 pi r^2 h

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7 0
3 years ago
Comfy inn earned $218,310 in taxable income for the year. how much tax does the company owe? $86,311.20 $85,140.90 $68,390.90 $6
Mrrafil [7]
see the correct  question in the attached file

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6 0
3 years ago
Find the value of the determinant using the method of expansion by minors; expand on the third row
valkas [14]

For the matrix

\begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}

the determinant using the method of expansion by minors, expanding on the third row is:

\det \begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}=a_{31}\det \begin{bmatrix}{a_{12}} & {a_{13}} & {} \\ {a_{22}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}-a_{32}\det \begin{bmatrix}{a_{11}} & {a_{13}} & {} \\ {a_{21}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}+a_{33}\det \begin{bmatrix}{a_{12}} & {a_{12}} & {} \\ {a_{22}} & {a_{22}} & {} \\ {} & {} & {}\end{bmatrix}

Answer:

First, we compute the determinants of the minors:

\begin{gathered} \det \begin{bmatrix}{0} & {4} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=0+4=4, \\ \det \begin{bmatrix}{1} & {4} & {} \\ {1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=3-4=-1, \\ \det \begin{bmatrix}{1} & {0} & {} \\ {1} & {-1} & {} \\ {} & {} & {}\end{bmatrix}=-1-0=-1. \end{gathered}

Therefore:

\det \begin{bmatrix}{1} & {0} & {4} \\ {1} & {-1} & {3} \\ {0} & {5} & {-2}\end{bmatrix}=0\times4-5\times(-1)+(-2)\times(-1)=5+2=7.

3 0
1 year ago
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