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SIZIF [17.4K]
3 years ago
11

PLEASE HELPP!!

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

all the children at the park are older than 3 years old

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Which of the following sets are continuous? Please help
Alecsey [184]

Answer:

A, C and D are continuous

Step-by-step explanation:

A is a set of any number x which 30 < x <=45

B is a set that contains only 3 and 7

C is a set of any number x which 60 <= x < 100

D is a set of any number x which -infinity < x < + infinity

E is a set that contains only even whole numbers

A continuous data set is a quantitative data set representing a scale of measurement that can consist of numbers other than whole number, like decimals and fractions.

7 0
3 years ago
How do I solve this?
Artemon [7]

a^2 - b^2 = (a + b)(a - b)

In this case

49x^4y^2 - 4z^2

= (7x^2y)^2 - (2z)^2

= (7x^2y + 2z)(7x^2y - 2z)

Factors are (7x^2y + 2z) and (7x^2y - 2z)

Answer:

D) 7x^2y + 2z

8 0
3 years ago
Simplify -4.5 + (-1.5)
mojhsa [17]

-4.5 + (-1.5)

-4.5 + 1.5

-6

5 0
3 years ago
Read 2 more answers
Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

<em>7. 2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}</em>

<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

3 0
3 years ago
Read 2 more answers
Show me how to find the answer to 6x1/3
mamaluj [8]

Answer:

2

Step-by-step explanation:

Simplify. Remember to follow PEMDAS and the left-> right rule.

In this case, multiply the whole number (6/1) with the numerator (1)

6 x 1 = 6

Next, simplify by dividing 6 with 3:

6/3 = 2

2 is your answer.

~

7 0
4 years ago
Read 2 more answers
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