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2 years ago

PLEASE HELPP!!

Mathematics

1 answer:

klio [65]2 years ago

7 0

Answer:

all the children at the park are older than 3 years old

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Please help with simple probability question. Extra points & brainliest. Thanks in advance.

kodGreya [7K]

The answer is B) 1/3.

There are 6 faces on a rectangular prism, each of which is a rectangle.

The area of the front and back is given by 25(8) = 200 sq. cm.
The area of the bottom and top is given by 25(4) = 100 sq. cm.
The area of the right and left is given by 4(8) = 32.

There are 2 faces out of 6 with an area that is not a multiple of 100; 2/6 = 1/3.

3 0

3 years ago

shyla was buying gifts for each of her 8 cousins. she bought everyone either a ring for $6 or a toy for $7. If she spent a total

Stella [2.4K]

7 * 5 = 35
6 * 3 = 18
________+
53

8 0

3 years ago

I need help with question number three can someone help me please I need to get this right

DENIUS [597]

Answer:

False

Step-by-step explanation:

The included side in ASA is inside between the angles being used

4 0

3 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago

a ladder leans against the sufe of a house. the angle of elevation of the ladder is 70 degrees when the bottom of the ladder is

nekit [7.7K]

Answer:

≈ 35.1 ft

Step-by-step explanation:

The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°

Using the cosine ratio, with l being the length of the ladder.

cos70° = $\frac{adjacent}{hypotenuse}$ = $\frac{12}{l}$ ( multiply both sides by l )

l × cos70° = 12 ( divide both sides by cos70° )

l = $\frac{12}{cos70}$ ≈ 35.1 ( to the nearest tenth )

The ladder is approx 35.1 ft long

4 0

3 years ago