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Allisa [31]
1 year ago
10

How do you turn 2x+3y=20 into slope intercept form?

Mathematics
1 answer:
IRISSAK [1]1 year ago
6 0

Answer:

The slope intercept form of the equation is:

y=-\frac{2}{3}x+\frac{20}{3}

Explanation:

Given the equation;

2x+3y=20

We want to re-write it in slope-intercept form;

\begin{gathered} y=mx+b \\ m=\text{slope} \\ b=\text{ y-intercept} \end{gathered}

To do that, let us make y the subject of formula in the given equation;

subtract 2x from both sides;

\begin{gathered} 2x-2x+3y=-2x+20 \\ 3y=-2x+20 \end{gathered}

then divide both sides by 3 ( the coefficient of y);

\begin{gathered} \frac{3y}{3}=\frac{-2x}{3}+\frac{20}{3} \\ y=-\frac{2}{3}x+\frac{20}{3} \end{gathered}

Therefore, the slope intercept form of the equation is;

y=-\frac{2}{3}x+\frac{20}{3}

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Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2​
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Answer:

-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

a_n=a_1+(n-1)d

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

a_1=-10\\d=-2

substitute

a_n=-10+(n-1)(-2)

a_n=-10-2n+2

a_n=-2n-8

so

<u><em>Find the first ten terms</em></u>

a_1=-10

For n=2 ----> a_2=-2(2)-8=-12

For n=3 ----> a_3=-2(3)-8=-14

For n=4 ----> a_4=-2(4)-8=-16

For n=5 ----> a_5=-2(5)-8=-18

For n=6 ----> a_6=-2(6)-8=-20

For n=7 ----> a_7=-2(7)-8=-22

For n=8 ----> a_8=-2(8)-8=-24

For n=9 ----> a_9=-2(9)-8=-26

For n=10 ----> a_1_0=-2(10)-8=-28

The sequence is

-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...

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Answer:

43,300

Step-by-step explanation:

Starting with 2 since its in the hundredths and going over one place to the tenths, we see 7 <em>is </em> greater than 5 so we make the 2 a 3 and replace everything after with 0's

43,300!!

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3 years ago
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