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ddd [48]
3 years ago
15

Find the solution of 4x^2-4x-1=0

Mathematics
1 answer:
just olya [345]3 years ago
4 0

4x^{2} -4x - 1 = 0

To solve for the zeros you can use the quadratic formula:

\frac{-b plus/minus\sqrt{b^{2}-4ac } }{2a}

a = 4

b = -4

c = -1

\frac{-(-4) plus/minus\sqrt{(-4)^{2}-4(4)(-1) } }{2(4)}

\frac{4 plus/minus\sqrt{16+16 } }{8}

\frac{4plus/minus\sqrt{32} }{8}

\frac{4plus/minus4\sqrt{2 } }{8}

\frac{1 plus/minus\sqrt{2} }{2}

Hope this helped!

~Just a girl in love with Shawn Mendes

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