Find the value of x x=?

* A Frog sits on a number line at point −10. It is allowed to make up to 4 jumps. First, it can make a jump of 8 units in either

Alika [10]

Answer and explanation:

Assuming the frog jumps from -10 for all jumps, if the frog decides to make all 4 jumps then :

8 units jump= -2 or -18

4 units jump= -6 or -14

2 units jump= -8 or -12

1 unit jump = -9 or -11

If the frog decides to make one jump then skip the others then:

Either it makes 8 units jump= -2 or -18

Or 4 units jump= -6 or -14

Or 2 units jump= -8 or -12

Or 1 unit jump = -9 or -11

If it decides to make 2 jumps and skip the others then:

Either it makes 8 units jump= -2 or -18

and 4 units jump= -6 or -14

Or 2 units jump= -8 or -12

and 1 unit jump = -9 or -11

Or any other mix of units of jump twice

If it decides to make 3 jumps and skip the others then:

Either it makes 8 units jump= -2 or -18

and 4 units jump= -6 or -14

and 2 units jump= -8 or -12

Or 1 unit jump = -9 or -11

and 4 units jump= -6 or -14

and 2 units jump= -8 or -12

Or any other mix of 3 jumps

If it decides to make no jump at all then the frog would remain at -10

8 0

3 years ago

Repeat the following procedure for the four given numbers .

Volgvan

3
multiply by 4
12
add 12
24
divide by 2
12
subtract 6
6

number 6 : 6(4) = 24... + 12 = 36...36/2 = 18.....- 6 = 12
number 8 : 8(4) = 32....+ 12 = 44...44/2 = 22....- 6 = 16
number 12: 12(4) = 48....+ 12 = 60...60/2 = 30....-6 = 24

well...by following these steps, it appears the original number doubles as a result.

4 0

4 years ago

Read 2 more answers

Length 12.2 height 14.7 volume 1,614.06 what is the width

sergejj [24]

9, 1,614.06 divided by 12.2 then by 14.7, then you get 9 the missing link

8 0

4 years ago

NO LINKS!!! What is the equation of these two graphs?

S_A_V [24]

Answer:

$\textsf{1.} \quad y=-\dfrac{1}{30}x^2+\dfrac{1}{2}x+\dfrac{68}{15}\:\:\textsf{ where}\:\:x \geq \dfrac{15-\sqrt{769}}{2}\\\\\quad \textsf{or} \quad y=2\sqrt{x+5}$

$\textsf{2.} \quad y=-|x+1|+5$

Step-by-step explanation:

<h3>Question 1</h3>

Method 1 - modelling as a quadratic with restricted domain

Assuming that the points given on the graph are points that the curve passes through, the curve can be modeled as a quadratic with a limited domain. Please note that as the x-intercept has not been defined on the graph, I am not including this in this first method.

Standard form of a quadratic equation:

$y=ax^2+bx+c$

Given points:

(-4, 2)
(-1, 4)
(4, 6)

Substitute the given points into the equation to create 3 equations:

Equation 1 (-4, 2)

$\implies a(-4)^2+b(-4)+c=2$

$\implies 16a-4b+c=2$

Equation 2 (-1, 4)

$\implies a(-1)^2+b(-1)+c=4$

$\implies a-b+c=4$

Equation 3 (4, 6)

$\implies a(4)^2+b(4)+c=6$

$\implies 16a+4b+c=6$

Subtract Equation 1 from Equation 3 to eliminate variables a and c:

$\implies (16a+4b+c)-(16a-4b+c)=6-2$

$\implies 8b=4$

$\implies b=\dfrac{4}{8}$

$\implies b=\dfrac{1}{2}$

Subtract Equation 2 from Equation 3 to eliminate variable c:

$\implies (16a+4b+c)-(a-b+c)=6-4$

$\implies 15a+5b=2$

$\implies 15a=2-5b$

$\implies a=\dfrac{2-5b}{15}$

Substitute found value of b into the expression for a and solve for a:

$\implies a=\dfrac{2-5(\frac{1}{2})}{15}$

$\implies a=-\dfrac{1}{30}$

Substitute found values of a and b into Equation 2 and solve for c:

$\implies a-b+c=4$

$\implies -\dfrac{1}{30}-\dfrac{1}{2}+c=4$

$\implies c=\dfrac{68}{15}$

Therefore, the equation of the graph is:

$y=-\dfrac{1}{30}x^2+\dfrac{1}{2}x+\dfrac{68}{15}$

$\textsf{with the restricted domain}: \quad x \geq \dfrac{15-\sqrt{769}}{2}$

Method 2 - modelling as a square root function

Assuming that the points given on the graph are points that the curve passes through, and the x-intercept should be included, we can model this curve as a square root function.

Given points: