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2 years ago

What are the odds of choosing a red marble from a bag that contains two blue marbles, one green marble and four red marbles?

Mathematics

1 answer:

Alisiya [41]2 years ago

4 0

Answer:

4:3

Step-by-step explanation:

You count up all the red marbles which equals 4 and put them on one side, then you add up all the rest of the marbles same color or not which equals 3 and put it on the other side of the 4

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If 15 counters are the whole set how many are three fifths of the set?

Travka [436]

$\frac{3}{5}\ of\ 15=\frac{3}{5}\times15=\frac{3}{5}\times\frac{15}{1}=\frac{3\times15}{5\times1}=\frac{3\times3}{1\times1}=\frac{9}{1}=\boxed9$

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2 years ago

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nirvana33 [79]

Answer:

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2 years ago

Blank percent of 50 shirts

Dmitrij [34]

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8 0

2 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

2 years ago

Read 2 more answers

1. How many groups of days are in 1 week?

wolverine [178]

Answer:

(14 groups)

14 divided by 7 = 2

Therefore 14 is your answer

Step-by-step explanation:

lol that's all I got

3 0

2 years ago