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professor190 [17]

4 years ago

15

In a shipment of toys from a manufacturer. The probability that a toy is defective is 1/50. If Marie selects 2 toys from a shipm

ent. What is the probability that both toys are defective?

2 answers:

GrogVix [38]4 years ago

8 0

Answer: The required probability is $\dfrac{1}{2500}.$

Step-by-step explanation: Given that in a shipment of toys from a manufacturer, where

the probability that a toy is defective is $\frac{1}{50}.$

We are to find the probability that both toys are defective, if Marie selects 2 toys from a shipment.

Since the events of selecting toys from a shipment are independent of each other,

therefore, the required probability that both toys are defective, if Marie selects 2 toys from a shipment will be

$P=\dfrac{1}{50}\times\dfrac{1}{50}=\dfrac{1}{2500}.$

Thus, the required probability is $\dfrac{1}{2500}.$

sukhopar [10]4 years ago

7 0

The probability is 1/2500. (1/50)*(1/50)

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Aiden brought chocolate and vanilla cupcakes to school for his birthday. 12 students picked a vanilla cupcake and 88 students pi

White raven [17]

Answer:

the percentage is 12%

Step-by-step explanation:

Given that

The 12 students picked up the vanilla cupcake

And, 88 students picked up the chocolate cupcake

We need to find out the percentage of the students picked up a vanilla cupcake

So, the percenatge is

= (12) ÷ (12 + 88) × 100

= 12 ÷ 100 × 100

= 12%

Hence, the percentage is 12%

8 0

3 years ago

A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbit

Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

$R(1) = 100(\frac{2}{5}.1 )$

$R(1) = 100(\frac{2}{5} )$

R(2) = $100(\frac{2}{5}.2 )$

$R(2) = 100(\frac{4}{5} )$

$\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )$

$\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]$

$\Delta R=$ 40

Difference of rabbits between first and second months is 40.

b. R(0) = 100( $\frac{2}{5} .0$ )

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = $100(\frac{2}{5}.10 )$

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

$500=100(\frac{2}{5}.t )$

$\frac{500}{100}=\frac{2}{5}.t$

$t = \frac{500.5}{100.2}$

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0

3 years ago

2x divided by x+5 less than or equal to 0

coldgirl [10]

It is more than 0, because you cancel the x, and you get 2+5, which is 7

4 0

3 years ago

What are the solutions of the system y=x^2+3x-4 y=2x+2

ra1l [238]

Hope this would help you

8 0

4 years ago

13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas

Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

$5+5^{2}=30$ (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

$5^{1}+5^{2}+5^{3}+...+5^{x}>19000$ (II)

Buscamos el valor de $x$ que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

$5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000$

$19530>19000$

El valor de $x$ que satisface (II) es $x=6$ .

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro $x=6$ , el número de horas que pasaron son 5 horas (1 menos que el valor de $x$ )

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0

4 years ago