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Gnesinka [82]
3 years ago
13

If (a,b) is the vertex of the parabola whose equation is y= (x+3)^2 +3, what is the value of a+b?

Mathematics
1 answer:
Lerok [7]3 years ago
6 0
The vertex is (-3,3),so a =-3, b=3. a+b=0
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Jimmy invests $2500 in an account with a 5% interest rate, making no other deposits or withdrawals. What will Jimmy’s account ba
Alik [6]

Answer:

We conclude that the total amount accrued, principal plus interest,  from compound interest on an original principal of  $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.

Step-by-step explanation:

Given

Principle P = $2500

Interest rate r = 5% = 0.05

Time period t = 8 years

To determine

Accrue Amount A = ?

Using the compound interest equation

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where:

A represents the Accrue Amount

P represents the Principal Amount

r represents the interest rate

t represents the time period in years

n represents the number of compounding periods per unit t

Important tip:

  • Given that the interest is compounded 6 times each year, therefore, the value of n = 6.

now substituting P = 2500, r = 0.05, t = 8 and n = 6 in the equation

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

A=2500\left(1+\frac{0.05}{6}\right)^{\left(6\right)\left(8\right)}

\:A=2500\left(1+\frac{0.05}{6}\right)^{48}

A=2500\times 1.48935      ∵  \left(1+\frac{0.05}{6}\right)^{48\:\:}=1.48935

A=\:3723.38 $

Therefore, we conclude that the total amount accrued, principal plus interest,  from compound interest on an original principal of  $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.

8 0
2 years ago
A function which is used to represent a problem, and which can be used to solve the problem, is called a ____.
algol [13]

Answer:

i think it would be a model.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve for x and y matrix
charle [14.2K]

Answer:

x=-1

y=5

Step-by-step explanation:

\begin{pmatrix}x&y\\ \:-1&4\end{pmatrix}\begin{pmatrix}2&5\\ \:4&1\end{pmatrix}=\begin{pmatrix}18&0\\ \:14&-1\end{pmatrix}

\begin{pmatrix}x&y\\ -1&4\end{pmatrix}\begin{pmatrix}2&5\\ 4&1\end{pmatrix}

=\begin{pmatrix}x\times \:2+y\times \:4&5x+y\\ 14&-1\end{pmatrix}

=\begin{pmatrix}18&0\\ 14&-1\end{pmatrix}

\begin{bmatrix}x\times \:2+y\times \:4=18\\ 5x+y=0\end{bmatrix}

x=-1

y=5

<u>OAmalOHopeO</u>

8 0
3 years ago
The area of a rectangular fountain is x2 + 9x + 20 square feet. A 3-foot walkway is built around the fountain. Find the dimensio
Leto [7]

Answer:

(x+11) by (x+10)

Step-by-step explanation:

We know that Area = Length x width

Given: Area = x²+9x+20

Lets sort this out first

Area = x²+5x + 4x + 20

Area = x(x+5) + 4(x+5)

Area = (x+5) (x+4)

Therefore, it is concluded that:

Length 'l' = (x+5) feet

Width 'w' = (x+4) feet

if a 3-foot walkway is built around the fountain, we'll add 3 feet on both sides

Therefore,

Outer Length = (x+5+3+3) = (x+11) feet

Outer Width = (x+4+3+3) = (x+10) feet

Answer:

The fountain is (x+5) by (x+4).  

dimensions of the outside border of the walkway are (x+11) by (x+10)

8 0
3 years ago
I’m confused can ya help me
Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of  x² = 1

b=  co efficient of x = 3

c = constant = -3

roots = (-b ± \sqrt{b-4ac})/2a

    = (-3±\sqrt{3^{2}-4*1*[-3]} )/2*1

    = (-3±\sqrt{9+12})/2

    = (-3±√21)/2

  x = \frac{-3+\sqrt{21}}{2}     ; x =\frac{-3-\sqrt{21}}{2}

7 0
3 years ago
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