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Which is the equation of an ellipse centered at the origin with foci on x-axis, x-intercepts +7, -7 and y-intercepts +2,
1 answer:
We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
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Given 12−(−2) over a line 12−6÷2
We can use PEMDAS rule and solve the expression in the order as given below:-
1. Parentheses
2. Exponents
3. Multiplication
4. Division
5. Addition
6. Subtraction
Now solving for given expression:-
So final answer is 14/9 i.e. 14 over 9.