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Fofino [41]
3 years ago
12

Absolute value |2x-3|=-1

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
8 0

Answer:

No solution.

Step-by-step explanation:

Absolute value cannot be less than 0

tigry1 [53]3 years ago
4 0

Answer:

x = 1

Step-by-step explanation:

  1. Simplify: 2x - 3 = -1
  2. Add 3 to each side, so it now looks like this: 2x = 2
  3. Divide each side by 2 to cancel out the 2 next to x. It should now look like this: x = 1

I hope this helps!

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Step-by-step explanation:

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7 0
3 years ago
Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par
Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that P(A) = 0.8, P(B) = 0.6

The probability that at least one part works for one year is 0.9.

This means that: P(A \cup B) = 0.9

We also have that:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

0.9 = 0.8+0.6 - P(A \cap B)

P(A \cap B) = 0.5

Calculate the probability that part B works for one year, given that part A works for one year.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0
3 years ago
Anybody help me please
GrogVix [38]

Answer:

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7 0
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Read 2 more answers
Evaluate the expression for x=5
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Answer:

There is not enough here to answer this problem

Step-by-step explanation:

Sorry : (

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