The quadratic formula is
.
From the problem, a is 1, b is -1, and c is 12. Plugging in these values gives:
![x=\frac{-(-1(-1)\pm\sqrt{(-1)^2-4(1)(12)} }{2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-1%28-1%29%5Cpm%5Csqrt%7B%28-1%29%5E2-4%281%29%2812%29%7D%20%7D%7B2%281%29%7D)
Because there is a square root of a negative number, there is no solution.
Answer:
1/3x
Step-by-step explanation:
Subtract x by x and y by y to find the distance/difference
36 163
24, 127
= 12/36 = rise/run
Now reduce to find the slope, reduce until you can't anymore.
12/36
6/18
3/9
1/3 (that's your slope)
1/16. that is the value that has the most x's on the graph.
Answer:
0.3
Step-by-step explanation:
x is the number to be added to 0.7 to have a sum of 1.
![0.7 + x = 1](https://tex.z-dn.net/?f=0.7%20%2B%20x%20%3D%201)
![x = 1 - 0.7](https://tex.z-dn.net/?f=x%20%3D%201%20-%200.7)
![x = 0.3](https://tex.z-dn.net/?f=x%20%3D%200.3)
Answer:
<h2>A = 36π yd² ≈ 113.04 yd²</h2><h2>C = 12π yd ≈ 37.68 yd</h2>
Step-by-step explanation:
The formula of an area of a circle:
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
The formula of a circumference of a circle:
![C=2\pi r](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r)
<em>r</em><em> - radius</em>
<em />
We have <em>r = 6yd</em>.
Substitute:
![A=\pi(6^2)=36\pi\ yd^2](https://tex.z-dn.net/?f=A%3D%5Cpi%286%5E2%29%3D36%5Cpi%5C%20yd%5E2)
![C=2\pi(6)=12\pi\ yd](https://tex.z-dn.net/?f=C%3D2%5Cpi%286%29%3D12%5Cpi%5C%20yd)
If you want round the answers, then use <em>π ≈ 3.14</em>
![A\approx(36)(3.14)=113.04\ yd^2](https://tex.z-dn.net/?f=A%5Capprox%2836%29%283.14%29%3D113.04%5C%20yd%5E2)
![C\approx(12)(3.14)=37.68\ yd](https://tex.z-dn.net/?f=C%5Capprox%2812%29%283.14%29%3D37.68%5C%20yd)