$270 are shared in the ratio 4:5. what is the greater share?
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Using the t-distribution, as we have the standard deviation for the samples, it is found that since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.
<h3>What are the hypothesis tested?</h3>At the null hypothesis, we test if they are equally effective teachers, that is, the subtraction of their means is 0, hence:
At the alternative hypothesis, we test if they are not equally effective teachers, that is, the subtraction of their means is not 0, hence:
For Mrs. Elite, we have that:
For Mrs. Bright, we have that:
For the distribution of differences, we have that:
The test statistic is given by:
In which is the value tested at the null hypothesis.
Hence:
Considering a<em> two-tailed test</em>, as we are testing if the mean is different of a value, with 30 + 25 - 2 = <em>53 df and a significance level of 0.1</em>, the critical value is of .
Since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.
To learn more about the t-distribution, you can take a look at brainly.com/question/13873630
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Answer:
By splitting the line segments into equal parts, we find that the length of the line segment formed by joining the mid-points is 5.5 units.
Step-by-step explanation:
Given lengths show that the length of JK is 5 units, KL is 4 units and LM is 6 units. Let the midpoint of JK be A. This means JK is splited into two equal parts JA and AK. Since the lengths of both the segments are same, it will be 5/2 = 2.5 units.
Now, let the midpoint of LM be B. So, we have two equal line segments LB and BM of length 6/2 = 3 units.
So, the length of the line segment formed by joining A and B will be 2.5 + 3 = 5.5 units
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