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dimulka [17.4K]
3 years ago
13

Is calcium oxide a Element or compound or mixture?

Chemistry
2 answers:
yawa3891 [41]3 years ago
8 0

Answer:

The answer is compound

Explanation:

Zolol [24]3 years ago
3 0

Answer:

compound

Explanation:

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What are the components of a nucleotide
balandron [24]

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components of a nucleotide - DNA and RNA

7 0
4 years ago
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How would making bigger the population of a coyote affect the population of both rabbits and grasses
ra1l [238]
If you were to make coyote population bigger it would first affect the rabbits because with there being more coyote's they have to bring more food for the pack and with the rabbits being hunted more and more the grass that the rabbits would eat, is not being eaten then the grass will grow more often and more longer.
That is the circle of life in the wild. 
3 0
3 years ago
A 4.000 g sample of an unknown metal, M, was completely burned in excess O2 to yield 0.02225 mol of the metal oxide, M2O3. What
Solnce55 [7]
4X + 3O₂ = 2X₂O₃

n(X₂O₃)=0.02225 mol
m(X)=4.000 g
x - the molar mass of metal

m(X)/4x=n(X₂O₃)/2

x=m(X)/{2n(X₂O₃)}

x=4.000/{2*0.02225)=89.89 g/mol

X=Y (yttrium)



7 0
4 years ago
The electron configuration 1s2 is correct for an element that has 2 electrons, both in the first principle energy level
Molodets [167]

Answer:

The answer is True

Explanation:

I got it right on my quiz, hope this helps!

5 0
3 years ago
Calculate the molar mass of nitrogen gas if 0.250 g of the gas occupies 46.65 ml at stp
Mashutka [201]
<span>pre-1982 definition STP: 120 g/mol post-1982 definition STP: 122 g/mol The answer to this question depends upon which definition of STP you're using. The definition changed in 1982 from 273.15 K at 1 atmosphere to 273.15 K at 10000 pascals. As a result the molar volume of a gas at STP changed from 22.4 L/mol to 22.7 L/mol. So let's calculate the answer using both definitions and see if your text book is 35 years obsolete. First, determine the number of moles of gas you have. Do this by dividing the volume you have by the molar volume. So pre-1982: 0.04665 / 22.4 = 0.002082589 mol post-1982: 0.04665 / 22.7 = 0.002055066 mol Now divide the mass you have by the number of moles. pre-1982: 0.250 g / 0.002082589 mol = 120.0428725 g/mol post-1982: 0.250 g / 0.002055066 mol = 121.6505895 g/mol Finally, round to 3 significant figures: pre-1982: 120 g/mol post-1982: 122 g/mol These figures are insanely large for nitrogen gas. So let's see if our input data is reasonable. Looking up the density of nitrogen gas at STP, I get a value of 1.251 grams per liter. The value of 0.250 grams in the problem would then imply a volume of about one fifth of a liter, or about 200 mL. That is over 4 times the volume given of 46.65 mL. So the verbiage in the question mentioning "nitrogen gas" is inaccurate at best. I see several possibilities. 1. The word "nitrogen" was pulled out of thin air and should be replaced with "an unknown" 2. The measurements given are incorrect and should be corrected. In any case, if #1 above is the correct reason, then you need to pick the answer based upon which definition of STP your textbook is using.</span>
6 0
3 years ago
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