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The question is incomplete, here is the complete question:
Assume that concentrated aqueous NH₃ has a density of 0.252 g/mL (0.252 g of NH₃ per mL of liquid). Calculate the volume of NH₃ required to contain 0.442 mol?
<u>Answer:</u> The volume of ammonia required is 29.82 mL
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Molar mass of ammonia = 17 g/mol
Moles of ammonia = 0.442 moles
Putting values in above equation, we get:
To calculate the volume of ammonia, we use the equation:
Density of ammonia = 0.252 g/mL
Mass of ammonia = 7.514 g
Putting values in above equation, we get:
Hence, the volume of ammonia required is 29.82 mL