Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
Answer:
c
Explanation:
we cannot say that either will die out, because we dont know the conditions. but we know that both sides out the mountian arent exactly the same, so we know they will evolve to adapt and grow with what they have
I believe that this
question has the following choices:
<span>> hydrogen- and helium-rich </span>
<span>> water vapor- and carbon dioxide-rich </span>
<span>> nitrogen- and oxygen-rich </span>
<span>> nitrogen-rich and oxygen-poor </span>
The correct answer among
the choices is that atmosphere III is:
<span>> nitrogen- and oxygen-rich </span>
Answer:
Two solid powders are combined and shaken. The substances form a mixture.