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valkas [14]
3 years ago
10

PLEASE HELP ME!! BRAINLIEST AND 60 POINTS

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0

\boxed{  \tt{its \: a \: straight \: line \: graph}}

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Delicious77 [7]

Answer:you need use a scale and the numbers that are provided of the dimensions of the room

Step-by-step explanation:

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The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2
rjkz [21]
The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2 units up to form polygon A′B′C′D′. Match each vertex of polygon A′B′C′D′ to its coordinates.Tiles
(2, 1)A′(2, -1)
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8 0
3 years ago
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4&gt; Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

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\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

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Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
Please give me the correct answer ​
vlada-n [284]
The exponent should be 6
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A rectangle and 2 congruent quarter circles were used to make the figure shown. Which measurement is closest to the area of the
dexar [7]

Answer:

109.3

Step-by-step explanation:

7 0
3 years ago
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