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valkas [14]
2 years ago
10

PLEASE HELP ME!! BRAINLIEST AND 60 POINTS

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
3 0

\boxed{  \tt{its \: a \: straight \: line \: graph}}

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Charge q is one unit of distance away from the source charge s. Charge p is two times further away. The force exerted between S
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Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p

a. 1/2

b. 2 times

c. 1/4

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Answer:

4 times

Step-by-step explanation:

Given the following :

Distance between q and S (r) = 1 unit

Distance between P and S (r) = 2 × 1 unit = 2

According to coliumbs law:

F = Ke(q1q2) /r^2

Where F = electrostatic force, Ke = coloumbs constant

q1,q2 = charges, r = distance between two charges

For q and S :

Fsq = Ke(q1q2) / 1^2

Fsq = Ke(q1q2) - - - - - equation 1

For P and S :

Fsp = Ke(q1q2) / 2^2

Fsp = Ke(q1q2) / 4 - - - - - equation 2

Dibiding equation 1 by equation 2

Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4

Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)

Fsq / Fsp = 4 / 1

Using cross multiplication

Therefore, Fsq = 4 × Fsp

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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220 - a = m

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