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3 years ago

A slope of -2 and a y-intercept of -7

Mathematics

2 answers:

rosijanka [135]3 years ago

8 0

Y=-2x-7
Y=mx+b where m is the slope and b is the y-intercept

Tanzania [10]3 years ago

3 0

Answer:

y = -2x - 7

Step-by-step explanation:

y = mx + b

m = slope = -2

b = y-int. = -7

Plug them in, you get y = -2x - 7

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Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is start fraction 1 over 6 e

Alona [7]

Answer: B. one-third

Step-by-step explanation:

Probability of picking a red marble, P(R) = 1/6

Probability of picking a yellow marble, P(Y) = 1/2

Therefore, the probability of picking a blue marble will be:

= 1 - (P(R) + P(Y))

= 1 - (1/6 + 1/2)

= 1 - (4/6).

= 1 - 2/3

= 1/3

The probability of picking a blue marble will be one third

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3 years ago

An experiment has four equally likely outcomes: E1, E2, Es, and E.Round your answers to three decimal places. a. What is the pro

V125BC [204]

Answer:

a. 0.25

b. 0.50

c. 0.75

Step-by-step explanation:

P(E1) = 0.25

P(E2) = 0.25

P(Es) = 0.25

P(E) = 0.25

a. Since there are 4 outcomes with the same probability of occurring, the probability of E occurring is:

$P(E) = \frac{1}{4}=0.25$

b. The probability of any two outcomes occurring is twice the probability of a single outcome occurring

$P(two\ outcomes) = 2*P(one\ outcome) = \frac{2}{4}=0.50$

c. The probability of any three outcomes occurring can be written as 100% minus the probability of the remaining outcome occurring

$P(three\ outcomes) = 1-P(one\ outcome) = 1-\frac{1}{4}=0.75$

6 0

4 years ago

Which is a correct first step for solving this equation -3x+2-5x-7=4x+2

Nataly_w [17]

Answer:

Your first step should be to separate the x's and the numbers.

This is how I would do it:

-3x+2-5x-7=4x+2

-3x-5x-4x=2-2+7

-12x=7

x=-7/12

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3 years ago

The vector wequalsaiplusbj is perpendicular to the line axplusbyequalsc and parallel to the line bxminusayequalsc. It is also tr

Likurg_2 [28]

Answer:

$\theta=45^{\circ}$

Step-by-step explanation:

We are given that the equation of lines

$x+\sqrt 3y=1$

$(1-\sqrt 3)x+(1+\sqrt 3)y=8$

According to question

The vector perpendicular to the lines is given by

$i+\sqrt 3j$ and $(1-\sqrt 3)i+(1+\sqrt 3)j$

Therefore, the angle between two vectors is given by

$cos\theta=\frac{a_1a_2+b_1b_2}{\sqrt{a^2_1+b^2_1}\sqrt{a^2_2+b^2_2}}$

Using the formula

$cos\theta=\frac{1(1-\sqrt 3)+\sqrt 3(1+\sqrt 3)}{2\times 2\sqrt 2}$

$cos\theta=\frac{1-\sqrt 3+\sqrt 3+3}{4\sqrt 2}=\frac{1}{\sqrt 2}$

$cos\theta=cos 45^{\circ}$

$\theta=45^{\circ}$

Hence, the acute angle between the lines is given by

$\theta=45^{\circ}$

3 0

3 years ago

Jeffrey is using a copy machine to make posters for a school play. The machine prints the posters at a constant rate. After 3 mi

My name is Ann [436]

I think the copy machine makes 36 posters per minute so making 396 posters would take 11 minutes

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3 years ago