Answer:.
Step-by-step explanation:nearest hundredth the answer for this question is joe mama
The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
Read more about functions at
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Just jump the gun and multiply -7 and the value of d
-2[7x^2-24]-31
I got
-14x^2+17
as the total answer btw...
Answer:
length of C'B' is 4 units
length of CB is 8 units
the larger hexagon is twice as large as the smaller; scale is 2:1
Step-by-step explanation: