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anzhelika [568]
3 years ago
15

A slope of -2 and a y-intercept of -7

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0
Y=-2x-7
Y=mx+b where m is the slope and b is the y-intercept
Tanzania [10]3 years ago
3 0

Answer:

y = -2x - 7

Step-by-step explanation:

y = mx + b

m = slope = -2

b = y-int. = -7

Plug them in, you get y = -2x - 7

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Expand and simplify<br>2(2y + 1) + 2(5y - 3)​
GarryVolchara [31]

Answer:

14y-4

Step-by-step explanation:

Distribute 2 to both the left and right side.

Combine like terms.

14y-4

7 0
3 years ago
Write an equation in slope-intercept from the line with slope 3/5 and y-intercept 1 . Then graph the line.
never [62]

Answer:

y=(3/5)x+1

Step-by-step explanation:

Slope-intercept form of a line is as follows

y=mx+c, where m is the slope of the line and c is the y intercept.

Hence the equation of the line is y=(3/5)x+1

3 0
2 years ago
 The area of a circle is less than 1 dm². Find the radius of the circle. The area of a circle is less than 1 dm². Find the rad
Ipatiy [6.2K]
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if you drop the radius to less than that, then the Area will also drop to less than 1 unit, in this case it happens to be a decimeter
5 0
3 years ago
What is the slope of the line that passes through the points (4, -9)(4,−9) and (8, -3) ?(8,−3)? Write your answer in simplest fo
faltersainse [42]

Answer:

\frac{3}{2}

Step-by-step explanation:

I am assuming that you mean (4,−9) and (8, -3).

m=\frac{rise}{run}=\frac{-3+9}{8-4}=\frac{6}{4}=\boxed{\frac{3}{2}}

Hope this helps.

6 0
2 years ago
Read 2 more answers
Find the area of a regular octagon with a side length of 4 cm.​
goblinko [34]

Answer:

77.25 cm^2

Step-by-step explanation:

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2a^2(1 + (sqrt2))

where a is the side

substitute 4 in for 'a'

6 0
2 years ago
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