Answer:
True.
Step-by-step explanation:
Let's see the definition of in-center of a triangle.
The in-center of a triangle is a point located in the center of the triangle. It is equal distance from all sides of the triangle.
Therefore, it is True.
If we draw line segments from in-center to each vertex of the triangle, it will bisect the angles.
Herewith I have attached the figure for your reference.
Answer:
Step-by-step explanation:
This is a parabola since a quadratic is a parabola. The standard form for a parabola is y = ax² + bx + c
but before we do that, we will use the vertex form, since it will make our work easier at the beginning.
First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be
y=-|a|(x - h)² + k
The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front. So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex: x = -7, y = 0, h = -3, k = 4
0 = a(-7 - (-3))² + 4 and
0 = a(-7 + 3)² + 4 and
0 = a(-4)² + 4 and
0 = a(16) + 4 and
0 = 16a + 4 and
-4 = 16a so
Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.
Now we will FOIL out what's inside the parenthesis to get
Simplify by distributing the -1/4 into the parenthesis:
Combine like terms to get
And there you go!