Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
I believe it was a rectangle I'm not sure test it out.
Answer: 13,333 snowflakes
Step-by-step explanation:
For this exercise let be "x" represents the number of snowflakes that will be in the fort.
According to the information given in the exercise, the weight of one block is 1 kilogram. Knowing that the fort must have 40 blocks, the total weight is:
Since each snowflake weighs 
grams, need to divide the total weight calculated above by the weight of a snowfake.
Therefore, through this procedure you get the following result:
Therefore, the there will be 13,333 snowflakes in the fort.
11 cm? Im not that good at this.. If im correct any of those would work
Answer:
the answer is d the person above is wrong.
Step-by-step explanation of the wrong answers: b is wrong because it will be 3,3,3,3,3,3,3,4,4,4,5,5,5,6,6. A is wrong because 3 isn't in the middle. C is wrong because then 6-2 is 4. There's your explanation.
