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worty [1.4K]
3 years ago
15

Work out an equation of the straight line with gradient 3 that passes through the point with coordinates (2, 4).

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

The answer is

\huge \boxed{y = 3x - 10}

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (2, 4) and the slope is 3

The equation of the line is

y - 4 = 3(x - 2) \\ y + 4 = 3x - 6 \\ y = 3x - 6 - 4

We have the final answer as

y = 3x - 10

Hope this helps you

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Answer:

coordinates of its image

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

Step-by-step explanation:

Reflect in y-axis means mirror it's points in the y -axis.

This means that the x coordinate of each point, changes only. Any mirrored point in the y-axis, will change only, by multiplying the x-coordinate by -1.

(Remember, zero multiplied by -1 remains 0).

Given are these points A, B, and C.

A = (4, -1)

B = (3,-3)

C = (0, 2)

After mirroring in the y- axis you get:

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

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