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3 years ago

Work out an equation of the straight line with gradient 3 that passes through the point with coordinates (2, 4).

Mathematics

1 answer:

Gnom [1K]3 years ago

3 0

Answer:

The answer is

$\huge \boxed{y = 3x - 10}$

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

$y - y_1 = m(x - x_1)$

where

m is the slope

( x1 , y1) is the point

From the question the point is (2, 4) and the slope is 3

The equation of the line is

$y - 4 = 3(x - 2) \\ y + 4 = 3x - 6 \\ y = 3x - 6 - 4$

We have the final answer as

$y = 3x - 10$

Hope this helps you

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Read 2 more answers

<img src="https://tex.z-dn.net/?f=%285%5E%7B3%7D%29%5E%7B-3%7D" id="TexFormula1" title="(5^{3})^{-3}" alt="(5^{3})^{-3}" align="

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$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( { {5}^{3} })^{ - 3} \\ \\ which\:means \:that \: {5}^{3}\: is \:multiplied \:thrice\: with\: itself\\ \\ = {5}^{3 \times - 3} \\ \\ = {5}^{ - 9} \\ \\= \frac{1}{ {5}^{9} } \\ \\ = \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5} \\ \\ = \frac{1}{1953125}$

<u>Note</u>:-

$( { {a}^{m} })^{n} = {a}^{m \times n}$

${a}^{ - m} = \frac{1}{ {a}^{m} }$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$

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