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Novosadov [1.4K]
3 years ago
13

A 12.000-gallon pool is being filled at a rate of 40 gallons per minute. At this rate, how many minutes will it take to fill thi

s pool 3/4 full?​
Mathematics
1 answer:
Irina18 [472]3 years ago
6 0

Answer:

2

Step-by-step explanation:

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Explain what the number 0 on the gauge represents and explain what the numbers above 0 represent
DaniilM [7]
0 is 500mg and the numbers above are larger.
3 0
4 years ago
The locations, given in polar coordinates, for two ships are (8 mi, 63º) and (8 mi, 123º). Find the distance between the two shi
Anna35 [415]
We know that

The arrangement forms an isosceles triangle with equal legs of 8 miles.
The angle between the legs is equal to

123-63=60°

 Therefore, the other two angles are
Angles = (180-60)/2 = 120/2 = 60°
It can, therefore, be noted that all angles are equal and thus the resulting triangle is actually an equilateral triangle and thus all the sides are equal.

Hence
the answer is
the distance between the two ships is 8 miles apart

alternative Method
Applying the law of cosines
<span>c²=a²+b²-2*a*b*cos C
</span>where
a=8 miles
b=8 miles
C is the angle between the legs-------> 123-63------> 60 degrees
c is the distance between the two ships
so
c²=8²+8²-2*8*8*cos 60------> c²=64-------> c=√64------> c=8 miles


5 0
4 years ago
Read 2 more answers
What is the the correct order for least to greatesed in these fractions,5/6,7/12 and 3/4
scZoUnD [109]

Answer:

7/12 3/4 5/6

Step-by-step explanation:

6 0
3 years ago
rancho middle school has an average of 23 3/8 students per teacher.write this mixed number as a decimal.
Bas_tet [7]
The answer is :
23 3/8 can be written as 23.375
3 0
4 years ago
A submersible traveling at a depth of 250 feet dives at an angle of 15 degrees with respect to a
kipiarov [429]

Answer:

\boxed{\text{652 ft}}

Step-by-step explanation:

The submersible is diving at a down angle of 15° along the hypotenuse AC of triangle ABC.  

Its horizontal track along the surface AB is 1500 ft.

\begin{array}{rcl}\tan A & = &\dfrac{BC}{AC}\\\\\tan 15^{\circ} & = & \dfrac{a}{1500}\\\\0.2679 & = & \dfrac{a}{1500}\\\\a & = & 1500 \times 0.2679\\& = & \textbf{402 ft}\\\end{array}

The submersible was already at a depth of 250 feet when it began the dive.

New depth = 250 + 402 = 652 ft

\text{The depth after the dive is }\boxed{\textbf{652 ft}}

6 0
4 years ago
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