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Mice21 [21]
3 years ago
13

While completing a multiplication problem I need to know how to do it by associative

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Associative property Says that you can add or multiply regardless of how the numbers are group

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Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Yuliya22 [10]

Answer/Step-by-step explanation:

1. \frac{(-2)^{-5}}{(-2)^{-10}}

Apply the Quotient rule: i.e. \frac{x^n}{x^m} = x^{n - m}

= (-2)^{-5 - (-10)} = (-2)^5} = -32

2. 2^{-1} * 2^{-4}

Apply the product rule: i.e. x^n * x^m = x^{n + m}.

= 2^{-1 + (-4)} = 2^{-1 - 4}

= 2^{-5}

Apply the negative exponent rule: i.e. x^{-n} = \frac{1}{x^n}

= 2^{-5} = \frac{1}{2^5}

= \frac{1}{32}

3. (-\frac{1}{2})^3 * (-\frac{1}{2})^2

Apply product rule

= (-\frac{1}{2})^{3 + 2}

= (-\frac{1}{2})^{5}

= -\frac{1^5}{2^5}

= -\frac{1}{32}

4. \frac{2}{2^{-4}}

Apply the rules of 1 and quotient rule

= 2^{1 - (-4)}

= 2^{1 + 4}

= 2^{5} = 32

6 0
3 years ago
What is the answer to this question?
Serga [27]

Answer: 87.5

Step-by-step explanation:

The Area formula for a Trapezium is

depicted in the two picture below.

As seen in the picture Area equals

A+B(h) all divided by 1/2 or simplistic terms 2.

A+b

A= ---------- (h)

2

So we need to plug our information in

as Depicted in the picture measurement A is first top side

And B is bottom base

so h IS the height of the figure. Its the middle line in the middle of the figure.

10+15

A= ________(7)

2

10+15=25

25*7=175

175/2=87.5

So your answer is

Area of ABCD is 87.5

6 0
3 years ago
Phil strung two sets of lights around the window of his store. The first set of lights blinks every 30s and the second every 45s
Amiraneli [1.4K]

Answer:

Every 90 seconds, the two sets of light blink together.

Step-by-step explanation:

Given that there are two sets of lights.

First light blinks at every 30s and

Second light blinks at every 45s

To find:

How often the sets of lights blink together?

Solution:

As per given statement,

First light blinks after 30s, 60s, <u>90s</u>, 120s, 150s, <u>180s</u>, ........

Second light blinks after 45s, <u>90s</u>, 135s, <u>180s</u>, .....

If we look at the common time, shown by underlining it, the two sets of light blink at the same time after 90s, 180s, ...... and so on.

So, the two lights blink together after every 90s.

This can also be solved by finding LCM (Least Common Multiple) of the two numbers i.e. 30 and 45.

Let us have a look at the factors of 30 and 45.

30 = 2 \times <u>3</u> \times <u>5</u>

45 = 3 \times <u>3</u> \times <u>5</u>

<u />

So, LCM = 2 \times 3 \times 3 \times 5 = <em>90</em>

<em></em>

So, after every <em>90s, </em>the lights will blink together.

5 0
3 years ago
HELP NEEDED ASAP!! PLEASE!!!
Aliun [14]

1/6 = 16.66/100

16% = 16/100

0.2 = 20/100

0.18 = 18/100

Lisa, Heidi, Jaydie, Martina

3 0
3 years ago
Evaluate if x = 2, y = 4, and z = 3. <br>x2 + xyz
ololo11 [35]

Answer:

28

Step-by-step explanation:

If x=2 then 2x2 is 4

Plus 2x4x3= 28

Hope this helps! :D

6 0
2 years ago
Read 2 more answers
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