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Gala2k [10]
2 years ago
14

PLSSSSSSSSSSSSSSSSSSSSS

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
4 0

I believe that the correct answer would be A

Hope this helped love <3

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Please answer this question
AfilCa [17]

Answer:

it is C

Step-by-step explanation:

4 0
2 years ago
URGENT: PLEASE HELP!
vazorg [7]

To solve this problem, we are going to set up an equation. However, first we need to convert the percentages to decimals by dividing by 100.

15% = 0.15 , 7.5% = 0.075

Now, we should substitute in our given information into our equation and let our unknown value be equal to the variable x.

0.15(500) = 0.075x

Then, we should simplify our equation by multiplying together the two factors on the left side of the equation.

75 = 0.075x

Finally, we should divide both sides of the equation by 0.075 to get the variable x alone.

x = 1000

Therefore, your answer is 1000.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Plz help will give brainliest
alukav5142 [94]
You simply divide 32 ÷ 4 = 8, for problem A
5 0
3 years ago
I tried 90 but it’s not right, what would it be? HELP PLEASE!!!!
dangina [55]

Answer:

  m∠DBF = 92°

Step-by-step explanation:

The given statements tell you that points E and F are midpoints of their respective sides of the triangle. Hence EF is parallel to AB and ...

  ΔABC ~ ΔEFC

That means ∠DBF ≅ ∠EFC and their measures are 92°.

3 0
3 years ago
How many 'words' can be made from the name ESTABROK with no restrictions
Bumek [7]

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

<h3>How to determine the number of ways</h3>

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Learn more about permutation here:

brainly.com/question/4658834

#SPJ1

6 0
1 year ago
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