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Sedaia [141]
3 years ago
11

The Bohr effect:_____.

Chemistry
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

b. contributes to binding of O2 by hemoglobin in lungs and release of O2 from hemoglobin in tissues.

Explanation:

  • The Bohr effect is a phenomenon described by Christian Bohr. Is an affinity that binds oxygen and hemoglobin and is inversely related to the concentration of carbon dioxide. As CO2 reacts with water and an increase in CO2 results in a decrease in blood ph.
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Which of the following is not balanced?
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Is it asking which is or isn’t balanced
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PLEASE HELP
-Dominant- [34]

Answer:

The answer is SiO2

Explanation:

Silocon dioxide is written without a 1 after the silocon and with a 2 after the oxygen.

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4 years ago
Suppose a mercury thermometer contains 3.250g of mercury and has a capillary that is 0.180mm in diameter.. How far does the merc
Helga [31]
1) You need to get volume of both temperatures by using first attached formula V= Mass/DensityV_1 = (3.250 g)/(13.596 g/(cm^3)) = .2390 cm^3
At 25 degrees C (V_2e have:

V_2  = (3.250 g)/(13.534 g/(cm^3)) = .2401 cm^3

2) Using the second formula you get the height of 0 degree 
h = V/(pi * r^2)


h_1 =(.2390 cm^3)/(pi*(.009 cm)^2)  = 939.2 cm

(radius in cm is (0.180 mm) / 2 * (1 cm)/(10 mm) or .009 cm

3) Then with h1 you can easily get the height of 25 degrees 
h_2 =(.2401 cm^3)/(pi*(.009 cm)^2) = 943.5 cm

 Subtract 943.5 cm - 939.2 cm, and obtain a rise in mercury height of 4.3 cm

5 0
3 years ago
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The "particles" of a gas are actually protons or electrons. true or false
Andrew [12]
False.

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7 0
4 years ago
Which of the following solutions would have the highest osmotic pressure?
Gennadij [26K]

Answer:

Option d. 0.10 m Cr₂(SO₄)₃

Explanation:

Formula for the osmotic pressure is determined as:

π = M . R . T . i

So you have to take account the i (Van't Hoff factor, numbers of ions dissolved)

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Zn(CH₃COO)₂  →  1Zn²⁺  + 2CH₃COO⁻

In this case, the i is 3. (you see, the stoichiometry of ions)

Cr₂(SO₄)₃ →  0.10 m

Chromium sulfate is dissociated:

Cr₂(SO₄)₃ →  2Cr³⁺  +  3SO₄⁻²

i = 5

BaI₂ → 0.16 m

BaI₂ →  1Ba²⁺  +  2I⁻

i = 3

8 0
4 years ago
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