The empirical formula is the simplest formula attainable while maintaining the ratio so it will be CH2.
Explanation:
The empirical formula of a chemical compound is the simplistic positive integer ratio of atoms being in a compound. A simple example of this thought is that the empirical formula of sulfur monoxide, or SO, would simply be SO, as is the empirical formula of disulfur dioxide, S2O2.
Answer:
One or unity or 1
Explanation:
For example,
1 min =60 s
If we divide each side of the equation by 1 min, we get
If we divide each side of the equation by 60 s, we get
Answer:
1.03M
Explanation:
mass/molar mass = moles of solution
50 g / (80+1) = 0.617 mol HBr
molarity*volume = moles
M*0.600 L = 0.617 mol
M = 0.617/0.600 = 1.03 M
The density of the carbon tetrachloride is 1.59 g/mL.
Mass of CCl₄ = 703.55 g – 345.8 g = 357.75 g
Density = mass/volume = 357.75 g/225 mL = 1.59 g/mL
Answer:
1.35 moles of O²⁻
21.6 grams of O²⁻
Explanation:
We know that the charge on Aluminium ion is +3 (i.e. Al³⁺) while, the charge on Oxide ion is -2 (i.e. O²⁻). Therefore, the overall neutral Al₂O₃ compound has 2 Al³⁺ ions and 3 O²⁻ ions. Since, we can say that,
1 mole of Al₂O3 contains = 3 moles of O²⁻ ions
So,
0.450 moles of Al₂O₃ will have = X g of O²⁻
Solving for X,
X = 0.450 mol × 3 mol ÷ 1 mol
X = 1.35 moles of O²⁻
As the mass of an atom is mainly due to the presence of protons and neutrons hence, the addition of two electrons (-ve 2 shows two gained electron) to Oxygen will make a negligible change to the atomic masss of Oxygen because electron is said to be almost 1800 times lighter than proton. Hence, the ionic mass of O²⁻ will be 16 g/mol and the mass of given moles is calculated as,
Mass = Moles × Ionic Mass
Mass = 1.35 mol × 16 g/mol
Mass = 21.6 g
