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Nikolay [14]
3 years ago
13

100 POINTS AND BRAINLIEST !!!!! (I need the answer ASAP) A school is planning to construct two rectangular play areas in the pla

yground.
The length of play area A must be 1 foot longer than four times its width. The width of play area B must be 2 feet longer than the width of play area A, and the length must be 2 feet longer than three times its own width. In addition, the areas of the two play areas must be equal.

Write a system of equations to represent this situation, where y is the area of the play areas and x is the width of play area A. Which statement describes the number and viability of the system’s solutions?

A.
The system has two solutions, and both are viable because they result in positive widths.
B.
The system has only one solution, but it is not viable because it results in a negative width.
C.
The system has two solutions, but only one is viable because the other results in a negative width.
D.
The system has only one solution, and it is viable because it results in a positive width.
Mathematics
2 answers:
IRINA_888 [86]3 years ago
5 0

Answer:

D.

Step-by-step explanation:

I'ts just reading the question over and over.

MakcuM [25]3 years ago
3 0

Answer:

The Answer is C

Step-by-step explanation:

I blessed you all and just guessed on the test on Plato/Edmentum and this was the right answer.

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Im trying to solve too

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100 pts question
bixtya [17]

Let x be the width

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3 years ago
The rate at which a quantity of a radioactive substance decays is proportional to the quantity of the substance. The constant of
Butoxors [25]

Answer:

\frac{dN}{dt} = λN           N(0) = 6

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Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing  the information briefly and stating the  variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality  is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays (\frac{dN}{dt}) is proportional to the quantity of the substance (N)  and λ is the constant of proportionality  is called the decay constant or decay rate :

\frac{dN}{dt} = λN          

N(t) = N₀e^(λt) ......equ 1

substituting the value of  N₀ = 6 into equation 1

N(t) = 6e^(λt)

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kari74 [83]
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I believe it’s the third answer!

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