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zzz [600]
3 years ago
11

Which of the following points is a solution to the system of linear inequalities?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0

Answer:

B

Step-by-step explanation:

2(-4)-1≤-5

-9≤-5

true

-(-4)-1>0

3>0

true

all the other options are false when u solve it

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9 (1/3)^n-1 what is the tenth term
NARA [144]

Answer:

a_{10}=\frac{1}{2187}

Step-by-step explanation:

Simply plug in 10 for <em>n</em>

9(1/3)¹⁰⁻¹

9(1/3)⁹

9(1/19683)

9/19683

a_{10}=\frac{1}{2187}

7 0
3 years ago
Determine the general solution of:<br><br> sin 3x - sin x = cos2x
SpyIntel [72]
Sin³ x-sin x=cos ² x

we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
              1     2      1      0
       -1         -1      -1                       z=-1
--------------------------------------
              1     1       0                       z=-1

Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
6 0
3 years ago
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
I need help with this question.
Nataly_w [17]

Answer:

Plot 2 2/5 at the 4th tick mark past 2

Plot 1 7/10 at the 7th tick mark past 1

5 0
2 years ago
A rental car agency rents cars for $32 per day. They also charge $0.15 per mile driven. If you are taking a 5-day trip and have
Verizon [17]
So it would be 600 miles you can drive within the limit of $250 and that would be $160 for the 5 day trip with $32 a day and 90 divided by $0.15 is 600 miles. 600 Miles is the answer.

6 0
3 years ago
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