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Aliun [14]
3 years ago
14

What is the 7.5% of 48000

Mathematics
2 answers:
dimaraw [331]3 years ago
4 0
48000 * 0.075 = 3600
nydimaria [60]3 years ago
3 0
- - To solve you want to multiply,

7.5*18000=<span>3600</span>

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Please help i will give brainliest!
iren [92.7K]
Area of square = 24cm²
⇒ Length = √24 

Find the diagonal of half the square:
a² + b² = c²
c² = (0.5√24)² + (√24)²
c² = 6 + 24
c² = 30
c = √30

The diagonal of half of the square is the radius of the circle.
⇒ radius = √30

Area of the semicircle = 1/2πr² = 1/2π(√30)² =15π

Answer: 15π²

5 0
3 years ago
how do I solve this quadratic simultaneous equation 2y+2x=7 and x^2-4y^2=8 it has two sets of solutions and I'm solving by both
Ghella [55]
These are all the possible answers i know from experience.

2x + 2y = 7
x^2 - 4y^2 = 8

2x = -2y + 7
x = -y + 7/2

(-y + 7/2)^2 - 4y^2 = 8

y^2 - 7y + 49/4 - 4y^2 = 8

0 = 3y^2 + 7y + 8 - 49/4

0 = 12y^2 + 28y + 32 - 49

0 = 12y^2 + 28y - 17

y = (-b ± √(b^2 - 4ac))/(2a)

y = (-28 ± √(28^2 - 4(12)(-17)))/(2(12))

Dividing by 2 is like dividing by √(4):

y = (-14 ± √(7*28 + (12)(17)))/(2*6)

y = (-7 ± √(7*7 + (3)(17)))/6

y = (-7 ± 10)/6 = 1/2 or -17/6

x = -y + 7/2 = 3 or 19/3

<span>Solutions are (3,1/2) and (19/3,-17/6)</span>
3 0
3 years ago
Read 2 more answers
At a military function, three cannons are fired at intervals of 12
Morgarella [4.7K]

Answer:

144 seconds

Step-by-step explanation:

To do solve this question, we must find the LCM (least common multiple) of 12, 16, and 18.

Let's start by prime factorizing (finding the prime factors) all the numbers.

12\rightarrow3*4\rightarrow2*2*3

16\rightarrow4*4\rightarrow2*2*2*2

18\rightarrow2*9\rightarrow2*3*3

Now, we must find the greatest quantity of each [prime] number and multiply them together to obtain the least common multiple.

Upon further evaluation of the [prime] factors, we can see that we need four 2s and two 3s. Therefore...

2*2*2*2*3*3=2^4*3^2=16*9=144

They will be fired together again after 144 seconds.

3 0
3 years ago
SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!’
ad-work [718]

Factoring this expression using the identity of a²-b² = (a+b)(a-b)

Given :-

25 - x²

<em>This can be broken down into:- </em>

... ( 5 )² - ( x )²

<em>In this case, a is 5 and b is x </em>

... ( 5 + x ) ( 5 - x ) Is the answer.

Hope it helps!!

7 0
3 years ago
Read 2 more answers
Question Progress
andreyandreev [35.5K]

The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

Step-by-step explanation:

The given is,

                  The sum of two numbers is 21

                   The second number is six times the first number

Step:1

          Let, m - First number

                  n - Second number

Step:2

        From given,

                  n - 6m     ( The second number is six times the first number )

        Equation becomes,

                  Sum = m + n

        Where,

                      21 = m + ( 6m )

                       21 = 7m

                       m = 3

        Substitute m value n becomes,

                        n = 6m

                           = (6 × 3)

                      n  = 18

Result:

          The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

                   

5 0
3 years ago
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