V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
No, it is not a valid inference because her classmates do not make up a random sample of the students in the school.
Answer:
the answer is 5500 but if not put 6000$
102 miles you subtract them and get the results
