3x-2y=-5
3y-4x=8
1) multiply the first equation by 3
3(3x-2y=-5) this will give you the new equation: 9x-6y=-15
2) multiply the second equation by 2
2(3y-4x=8) this should give you the equation: 6y-8x=16
3) combine both equations/ like terms
9x-6y=-15
6y-8x=16
4) -6y and 6y cancel out
9x=-15
-8x=16
5) 9x and -8x combine to make 1x or just x and -15 combined with 16 gives you just 1
6) we are now left with:
x=1
7) plug in the x to any of the two original equations ( i chose the first)
3x-2y=-5
3(1) - 2y = -5
3 - 2y = -5
-2y = -8
y = 4
When you plug in the x=1 you are given 3(1) - 2y = -5
Distribute the 3 and you should have 3 - 2y = -5
Subtract 3 from 3 (this cancels out) then from -5
This should leave you with -2y = -8 ( -3 and -5 add to -8)
Divide by -2 ( -2 divided by -2 cancels out)
-8 divided by -2 gives you 4 (two negatives make a positive)
So, y=4 and x=1
To check, plug in x=1 and y=4 into one equation. when you're done with that you can plug them into the other. when you plug them into the first equation you get -5=-5 which means they worked. when plugged into the second, the result is 8=8 which means x=1 and y=4 worked for both equations.
X-6<15
X<21
Draw an unfilled dot on 21, line with arrow pointing toward zero/negative values
Answer:
you multiply the quotient times the divisor and your awnser should be the same as the dividend
Step-by-step explanation:
.764 in percentage form is 76.4%
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of passengers that rest or sleep during a flight.
The sample taken is n=9 passengers and the probability of success, that is finding a passenger that either rested or sept during the flight, is p=0.80.
I'll use the binomial tables to calculate each probability, these tables give the values of accumulated probability: P(X≤x)
a. P(6)= P(X=6)
To reach the value of selecting exactly 6 passengers you have to look for the probability accumulated until 6 and subtract the probability accumulated until the previous integer:
P(X=6)= P(X≤6)-P(X≤5)= 0.2618-0.0856= 0.1762
b. P(9)= P(X=9)
To know the probability of selecting exactly 9 passengers that either rested or slept you have to do the following:
P(X≤9) - P(X≤8)= 1 - 0.8657= 0.1343
c. P(X≥6)
To know what percentage of the probability distribution is above six, you have to subtract from the total probability -1- the cumulated probability until 6 but without including it:
P(X≥6)= 1 - P(X<6)= 1 - P(X≤5)= 1 - 0.0856= 0.9144
I hope it helps!