On the Solve the equation interval [0, 27). COS X - 1 = -COS X <= U
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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The equation of the function is y = 4x + 5. Find the value of y when
x = 3
x = -2
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2><h3>Given:-</h3>y = 4x + 5 [Equation]
<h3>To Find:-</h3>The value of y when x = 3 , x = -2
<h2>Solution:-</h2>y = 4x + 5 [Given equation]
When x = 3 ,
y = 4 × 3 + 5 [Value of x is 3]
y = 12 + 5
<h3>y = 17 [Answer]</h3>Again, when x = -2 ,
y = 4 × (-2) + 5 [Value of x is -2]
y = -8 + 5
<h3>y = -3 [Answer]</h3>
Is the answer to your question
Answer:
Step-by-step explanation:
as given j=h and k=m then which expression for g is
as from attached image , we can see that its look like two right angle triangle
so from lower triangle we apply the pythagorean theorem .
which state that sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.
so small triangle ΔEBD
h² +k²= g² ---------------(1)
now from big triangle ΔABC
(j + h)² +(m + h)² =f²---------(2)
given j=h and k=m so from equation-2 we can find ,
(h + h)² +(k+ k)² =f²
(2h)² +(2k)²=f²
4h²+ 4k²= f²
4(h²+k²)= f² ----------(3)
now from equation 1 and 3 we can obtained .
4×g² =f²
take square root both side we get,
2×g=f
so g=f/2----- Answer
