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skelet666 [1.2K]
2 years ago
10

WILL GIVE BRAINLIEST please help

Mathematics
2 answers:
IgorLugansk [536]2 years ago
7 0

Answer:

First bullet point

Step-by-step explanation:

Travka [436]2 years ago
5 0

Answer: The first option (A)

Step-by-step explanation:

i did the math just plug in the numbers for x.

hope this helps pls mark me brainliest

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What does "a"equal to?
slamgirl [31]
Distribute on the left side
7.4a+22.2=3.2a+43.2
Subtract 3.2a from both sides
4.2a+22.2=43.2
Subtract 22.2 from both sides
4.2a=21
Divide both sides by 4.2
a=5
5 0
3 years ago
In the numerical sentence below, A = 8, D = 1/2 , and F = 1/4. What are the values B, C, and E if the sentence below is equivale
a_sh-v [17]
B=3; C=16; and E=4096.

Using the information we have gives us

8^B \times C^{\frac{1}{2}} = E^{\frac{1}{4}}

We know that:
8^B = 2;
\\
\\C^{\frac{1}{2}}=4;
\\
\\E^{\frac{1}{4}}=8

We know that 2³ = 8, so B = 3.

To "undo" a square root, we square the number; 4²=16, so C = 16.

To "undo" a fourth root, we raise the answer to the fourth power; 8⁴ = 4096, so E = 4096.
3 0
3 years ago
Read 2 more answers
Ppplllzzz hhhheeelllllllpppppp ​
timama [110]

Answer:

65

Step-by-step explanation:

Formula: 1/2bh

An isosceles triangle has at least 2 sides equal, so the blank side is 13.

base=10

height=13

13*10=130

half of that is 65

5 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
14x 1 =63 square root equation
soldier1979 [14.2K]
Add the one from the left to the 63 to get 64. Then divide both sides by 4 and get x^2=16. Take the square root of both sides to get x to equal 4.
4 0
2 years ago
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